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vlabodo [156]
3 years ago
11

Mike recently increased the size of his Jeep tires from the original 29 inch diameter to the larger 33.73 inch diameter. If Mike

didn't recalibrate his speedometer, how fast is he really going on the new tires when his speedometer shows he is traveling 60 mph?
a. 54.5 mph
b. 62.1 mph
c. 66.1 mph
d. 69.8 mph
Mathematics
2 answers:
Anastasy [175]3 years ago
4 0

Answer:

d. 69.8 mph

Step-by-step explanation:

Since, the ratio of the diameter of the tyre of a vehicle and its speed must be constant,

Given,

The original diameter of the tyre = 29 inch,

Original speed = 60 mph,

Thus, the ratio of diameter and the speed of the vehicle = \frac{29}{60}

New diameter of the tyre = 33.73 inch,

Let x be the new speed of the vehicle = \frac{33.73}{x}

\implies \frac{29}{60}=\frac{33.73}{x}

\implies x=\frac{33.73\times 60}{29}=69.79\approx 69.8\text{ mph}

Hence, the actual speed of the vehicle would be 69.8 mph.

OPTION D is correct.

coldgirl [10]3 years ago
3 0

Answer:

I believe it is C

Step-by-step explanation:

Please correct me if i am wrong ^w^

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2 years ago
Read 2 more answers
The coffee counter charges ?"$11.00" per pound for kenyan french roast coffee and ?"$13.00" per pound for sumatra coffee. How mu
zloy xaker [14]

Answer: The answer is 13 ponds of each type should be used.

Step-by-step explanation:  Given that the coffee counter charges $11.00 per pound for kenyan french roast coffee and $13.00 per pound for sumatra coffee. We are to find the quantity of each type that should be used to make a 26 pound blend that sells for $12.00 per pound.

Let 'x' pound and 'y' pound of  kenyan french roast coffee and sumatra coffee be used in the mixture of 26 pound.

So, we have

x+y=26,~~~~~~~~~~~~~~~~~~~~~~(A)\\\\11x+13y=12\times 26.~~~~~~~~~~(B)

Multiplying equation (A) by 11 and subtracting from equation (B), we have

13y-11y=12\times26-11\times26\\\\\Rightarrow 2y=26\\\\\Rightarrow y=13,

and from equation (A),

x=26-13=13.

Thus, 13 pounds of each type of coffee should be used.

8 0
3 years ago
PLEASE HELP ASAP
neonofarm [45]

Answer:

9 Quarters

8 Dimes

3 Nickels

Step-by-step explanation:

We let the number of quarters be q

number of dimes be d

and

number of nickels be n

Since quarters are worth 0.25, dimes are worth 0.10 and nickels are worth 0.05 and total worth is 3.20, we can write an equation as:

0.25q + 0.10d + 0.05n = 3.20

Next,

3 times as many quarters as Nickels, we can write:

q = 3n

and

5 more dimes than nickel, we can write:

d = n + 5

Substituting these last 2 equations in the first and solving for n gives us:

0.25q + 0.10d + 0.05n = 3.20

0.25(3n) + 0.10(n+5) + 0.05n = 3.20

0.75n + 0.10n +0.5 + 0.05n = 3.20

0.9n = 2.70

n = 2.70/0.9 = 3

n = 3

We know q = 3n, so

q = 3(3) = 9

Also, we know d = n + 5, which means:

d = 3 + 5 = 8

Thus,

There are:

9 Quarters

8 Dimes

3 Nickels

5 0
3 years ago
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