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marta [7]
3 years ago
8

While setting up a fireworks display, you have a tool at the top of the

Mathematics
1 answer:
atroni [7]3 years ago
8 0

Answer:

0.79 sec

Step-by-step explanation:

Given there is a tool at the top of the building which is dropped by a worker and it follows the following equation at every instant of time .

h(t)=-16t^{2} +h_{0}

where h_{0} =10 feet

We know that this height is measured from the base of the building which means that when the tool reaches the bottom of the building it has h = 0 feet.

Let this be done at time t

h(t) = 0

-16t^{2} +10=0

t^{2} =\frac{10}{16}

t=\frac{\sqrt{10} }{4}

t = 0.79 sec

Therefore the total time taken by the tool to reach the bottom of the building is 0.79 sec.

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A 2-column table with 8 rows. The first column is labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2, 3, 4. The
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Answer:

Option B.

Step-by-step explanation:

The given table of values is

x         f(x)

-3       -2

-2        0

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0         2

1          0

2        -8

3        -10

4        -20

We need to find the interval for which the function f(x) is positive.

From the given table it is clear that the value of function f(x) is negative before -2 and after 1.

The function positive between x=-2 and x=1. So, we can conclude that the function f(x) is positive for the interval (-2,1).

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3 years ago
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The standard for is 2000+ 1200
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Ms. Smith has 28 sixth graders and 35 seventh graders for Math. If she wants to break the two grades into identical groups witho
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3 years ago
Write an equation of a line that passes through the point (1, 2) and is perpendicular to the line y=-1/4x+2​
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3 years ago
(-6,8); perpendicular to y = -3/2x -1
UNO [17]

Answer:

y =  \frac{2}{3} x + 12

Step-by-step explanation:

y =  -  \frac{3}{2} x - 1

The gradient of a line is the coefficient of x when the equation of the line is written in the form of y=mx+c.

Thus, gradient of given line=-  \frac{3}{2}.

The product of the gradients of perpendicular lines is -1.

(Gradient of line)(-3/2)= -1

Gradient of line

- 1 \div ( -  \frac{3}{2} ) \\  =  - 1( -  \frac{2}{3} )  \\  =  \frac{2}{3}

Substitute m=\frac{2}{3} into y=mx+c:

y =  \frac{2}{3} x + c

To find the value of c, substitute a pair of coordinates.

When x= -6, y= 8,

8 =  \frac{2}{3} ( - 6) + c \\  \\ 8 =  - 4 + c \\ c = 8 + 4 \\ c = 12

Thus, the equation of the line is y =  \frac{2}{3} x + 12.

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