By what percent will the fraction increase if its numerator is increased by 60% and denominator is decreased by 20% ?
2 answers:
Answer:
100%
Step-by-step explanation:
Start with x.
x = x/1
Increase the numerator by 60% to 1.6x.
Decrease the numerator by 20% to 0.8.
The new fraction is
1.6x/0.8
Do the division.
1.6x/0.8 = 2x
The fraction increased from x to 2x. It became double of what it was. From x to 2x, the increase is x. Since x was the original number x is 100%.
The increase is 100%.
Answer:
33%
Step-by-step explanation:
let fraction be x/y
numerator increased by 60%
=x+60%ofx
=8x
denominator increased by 20%
=y+20%of y
so the increased fraction is 4x/3y
let the fraction is increased by a%
then
x/y +a%of (x/y)=4x/3y
or, a%of(x/y)=x/3y

therefore a=33
anda%=33%
You might be interested in
Answer:Median=7.42
Mean=7.61
Step-by-step explanation:




<h3>Remember these laws of integers:</h3>
- (+)(-)=(-)
- (-)(+)=(-)
- (-)(-)=(+)
- (+)(+)=(+)
Answer:
Below in bold.
Step-by-step explanation:
A.This is the number of combinations of 6 from 15
= 15C6
= 15! / (15-6)! 6!
= 5,005 ways.
B. This is the number of permutaions of 6 from 15:
= 15! / (15-6)!
= 3,603,600 ways.
Answer:
3 rings
Step-by-step explanation:
10 / 2 = 5 necklaces
(5/5) x 2 = 2 bracelets
10 - 5 - 2 = 3<u> rings</u>
The equation is already in Standard Form.