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Virty [35]
3 years ago
10

By what percent will the fraction increase if its numerator is increased by 60% and denominator is decreased by 20% ?

Mathematics
2 answers:
seropon [69]3 years ago
8 0

Answer:

100%

Step-by-step explanation:

Start with x.

x = x/1

Increase the numerator by 60% to 1.6x.

Decrease the numerator by 20% to 0.8.

The new fraction is

1.6x/0.8

Do the division.

1.6x/0.8 = 2x

The fraction increased from x to 2x. It became double of what it was. From x to 2x, the increase is x. Since x was the original number x is 100%.

The increase is 100%.

Feliz [49]3 years ago
4 0

Answer:

33%

Step-by-step explanation:

let fraction be x/y

numerator increased by 60%

=x+60%ofx

=8x

denominator increased by 20%

=y+20%of y

so the increased fraction is 4x/3y

let the fraction is increased by a%

then

x/y +a%of (x/y)=4x/3y

or, a%of(x/y)=x/3y

a\% =  \frac{x}{3y}  \times \frac{y}{x}

therefore a=33

anda%=33%

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Explanation:

Statements are numbered; reasons are in italics.

1. ABCD is a parallelogram with AB≅CD and BC≅AD. <em>Given; definition of a parallelogram</em>.

2. Diagonal AC ≅ diagonal CA. <em>Reflexive property of congruence</em>.

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5. Diagonal BD ≅ diagonal DB. <em>Reflexive property of congruence</em>.

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