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3 years ago

HELP ME PLEASE!!!!! ASAP

Mathematics

1 answer:

geniusboy [140]3 years ago

7 0

Answer:

Step-by-step explanation:

if you substitute the X's in each equation:

x=0 its the same answer for both and g(x) is always greater than f(x) for any number greater than 0 in this case

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A box of blueberries is 2/5 full. Janet and her friends had each eaten 1/10 of a box of blueberries. How many people are blueber

anyanavicka [17]

In this problem, we have to find the factor which will make (1 / 10) equal to (2 / 5). Therefore we can write it as:

x (1 / 10) = 2 / 5

where x is the number of people who ate the blueberries

x = (2 / 5) / (1 / 10)

x = 4

Therefore 4 people ate the blueberries.

7 0

3 years ago

Read 2 more answers

Please help its very hard

allochka39001 [22]

This histogram is skewed to the left and its distribution's center would be three (3).

<h3>What is a histogram?</h3>

A histogram is used to graphically represent a set of data points into user-specified ranges, especially through the use of rectangular bars.

In this scenario, we can infer the following about the histogram distribution's center, spread, and overall shape:

This histogram is skewed to the left.

Its distribution's center would be three (3).

The spread implies that more students are between 58-59 and 60-61 inches.

The shape shows that many of the values are at the lower end.

Read more on histogram here: brainly.com/question/21304143

#SPJ1

8 0

2 years ago

Find the critical points of the function f(x, y) = 8y2x − 8yx2 + 9xy. Determine whether they are local minima, local maxima, or

NARA [144]

Answer:

Saddle point: $(0,0)$

Local minimum: $(\frac{3}{8}, -\frac{3}{8})$

Local maxima: $(0,-\frac{9}{8})$ , $(\frac{9}{8},0)$

Step-by-step explanation:

The function is:

$f(x,y) = 8\cdot y^{2}\cdot x -8\cdot y\cdot x^{2} + 9\cdot x \cdot y$

The partial derivatives of the function are included below:

$\frac{\partial f}{\partial x} = 8\cdot y^{2}-16\cdot y\cdot x+9\cdot y$

$\frac{\partial f}{\partial x} = y \cdot (8\cdot y -16\cdot x + 9)$

$\frac{\partial f}{\partial y} = 16\cdot y \cdot x - 8 \cdot x^{2} + 9\cdot x$

$\frac{\partial f}{\partial y} = x \cdot (16\cdot y - 8\cdot x + 9)$

Local minima, local maxima and saddle points are determined by equalizing both partial derivatives to zero.

$y \cdot (8\cdot y -16\cdot x + 9) = 0$

$x \cdot (16\cdot y - 8\cdot x + 9) = 0$

It is quite evident that one point is (0,0). Another point is found by solving the following system of linear equations:

$\left \{ {{-16\cdot x + 8\cdot y=-9} \atop {-8\cdot x + 16\cdot y=-9}} \right.$

The solution of the system is (3/8, -3/8).

Let assume that y = 0, the nonlinear system is reduced to a sole expression:

$x\cdot (-8\cdot x + 9) = 0$

Another solution is (9/8,0).

Now, let consider that x = 0, the nonlinear system is now reduced to this:

$y\cdot (8\cdot y+9) = 0$

Another solution is (0, -9/8).

The next step is to determine whether point is a local maximum, a local minimum or a saddle point. The second derivative test:

$H = \frac{\partial^{2} f}{\partial x^{2}} \cdot \frac{\partial^{2} f}{\partial y^{2}} - \frac{\partial^{2} f}{\partial x \partial y}$

The second derivatives of the function are:

$\frac{\partial^{2} f}{\partial x^{2}} = 0$

$\frac{\partial^{2} f}{\partial y^{2}} = 0$

$\frac{\partial^{2} f}{\partial x \partial y} = 16\cdot y -16\cdot x + 9$

Then, the expression is simplified to this and each point is tested:

$H = -16\cdot y +16\cdot x -9$

S1: (0,0)

$H = -9$ (Saddle Point)

S2: (3/8,-3/8)

$H = 3$ (Local maximum or minimum)

S3: (9/8, 0)

$H = 9$ (Local maximum or minimum)

S4: (0, - 9/8)

$H = 9$ (Local maximum or minimum)

Unfortunately, the second derivative test associated with the function does offer an effective method to distinguish between local maximum and local minimums. A more direct approach is used to make a fair classification:

S2: (3/8,-3/8)

$f(\frac{3}{8} ,-\frac{3}{8} ) = - \frac{27}{64}$ (Local minimum)

S3: (9/8, 0)

$f(\frac{9}{8},0) = 0$ (Local maximum)

S4: (0, - 9/8)

$f(0,-\frac{9}{8} ) = 0$ (Local maximum)

Saddle point: $(0,0)$

Local minimum: $(\frac{3}{8}, -\frac{3}{8})$

Local maxima: $(0,-\frac{9}{8})$ , $(\frac{9}{8},0)$

4 0

3 years ago

Graph g is a translation of the graph of y= sin x (dashed line).a) write down the equation of g b) write down the coordinates of

labwork [276]

Answer:

a) $G(x)= \sin x + 2$

b) The coordinates of P are

$\displaystyle \left( \frac{3\pi}{2},1\right)$

Step-by-step explanation:

Translation

The dashed line shows the graph of the function

$y = \sin x$

This function has a maximum value of 1, a minimum value of -1, and a center value of 0.

Graph G shows the same function but translated by 2 units up, thus the equation of G is:

$\boxed{G(x)= \sin x + 2}$

b) The coordinates of P correspond to the value of

$x = \frac{3\pi}{2}$

The value of G is

$\displaystyle G(\frac{3\pi}{2})= \sin \frac{3\pi}{2} + 2$

Since

$\sin \frac{3\pi}{2}=-1$

$\displaystyle G(\frac{3\pi}{2})= -1+ 2=1$

The coordinates of P are

$\displaystyle \left( \frac{3\pi}{2},1\right)$

8 0

2 years ago

When the p-value is used for hypothesis testing, the null hypothesis is rejected if _____

pashok25 [27]

Answer:

Step-by-step explanation:

Here, we are to give the reason why we would reject the null hypothesis during the hypothesis testing.

In considering whether to accept the null hypothesis or reject the null hypothesis, we have to take into consideration two things.

The p-value and the alpha value. The p-value refers to the probability which is directly obtainable from the standard score which is referred to as the z-score while the alpha refers to the level of significance.

Now, when the p-value is less than alpha, we simply reject the null hypothesis and accept the alternative hypothesis. In a case however, we have the value of p greater than or equal to the significance level alpha, we simply accept the null hypothesis in this case.

The question asks for a rejection case and this can happen only when the p-value is less than the level of significance alpha

5 0

2 years ago