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2 years ago

7

Help plz and check just to make sue what is this

1 answer:

padilas [110]2 years ago

3 0

use cross products to solve

5* (n-9) = 8*n

distribute

5n-45 = 8n

subtract 5n from both sides

-45 = 3n

divide both sides by 3

-15 = n

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Mr. and mrs.storey drive 3200 miles in all during their vacation. mr.storey drove 3 times as many miles as mrs.storey how many m

vaieri [72.5K]

This can be solve by establishing equations.
let x be the miles mrs. storey drove
y be the miles mr storey drovee

the first equation is
y = 3x

second equation
x + y = 3200
then substitute equation 1

x + 3x = 3200
4x = 3200
x = 800 miles mrs storey drove
y = 3x = 2400 miles mr storey drove

5 0

3 years ago

HELP!!! Use the factor Theorem to determine whether the binomial x+1 is a factor of the polynomial function f(x) =2x^3-9x^2+13x-

Dovator [93]

ANSWER

A. No because f(c)=-30

EXPLANATION

The given polynomial is

$f(x) =2x^3-9x^2+13x-6$

If x+1 is a factor , then f(-1) must evaluate to zero.

$f( - 1) =2( - 1)^3-9( - 1)^2+13( - 1)-6$

$f( - 1) =2( - 1)-9( 1)+13( - 1)-6$

$f( - 1) = - 2-9 - 13-6$

$f( - 1) = -11 - 19$

$f( - 1) = - 30$

Since f(-1) is not equal to zero, x+1 is not a factor of

$f(x) =2x^3-9x^2+13x-6$

6 0

3 years ago

Dolores bought 3 tapes that cost $4.95 each. the tax on her purchase was %6. What was her total bill

SpyIntel [72]

Answer:15.741

Step-by-step explanation: 4.95*3= 14.85, 14.85* 0.06= 0.891+14.85=15.741

Hope it helped!

7 0

3 years ago

Solve for x.* (4x + 7)° (6x + 3)° Sign

Whitepunk [10]

24 x ^2 + 54 x + 21,

if you would like me to explain how to do it, I can in the comments.

3 0

3 years ago

Mathematically verify the outlier(s) in the data set using the 1.5 rule.

statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

$Q_1=\dfrac{11+13}{2}$

$Q_1=\dfrac{24}{2}$

$Q_1=12$

And

$Q_3=\dfrac{16+16}{2}$

$Q_3=\dfrac{32}{2}$

$Q_3=16$

The interquartile range is:

$IQR=Q_3-Q_1$

$IQR=16-12$

$IQR=4$

The data values lies outside the interval $[Q_1-1.5IQR,Q_3+1.5IQR]$ are known as outliers.

$[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]$

$[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]$

$[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]$

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

3 0

3 years ago