Answer:
After 48 hours amount left = 6.25 g
Explanation:
Given data:
Half life of potassium = 12 hours
Total mass = 100 g
Mass left after 48 hours = ?
Solution:
Number of half lives passed:
Number of half lives = Time elapsed / half life
Number of half lives = 48 hours/ 12 hours
Number of half lives = 4
At time zero = 100 g
At first half life = 100 g/ 2 = 50 g
At 2nd half life = 50 g/2 = 25 g
At 3rd half life = 25 g/2 = 12.5g
At 4th half life = 12.5 g/2 = 6.25 g
Answer:
a) Yes
b) Yes
c) Yes
d) Yes
Explanation:
a.
In the exons?
Yes mutant site will be expected. It will transcript-ed as well and it can be a polypeptide depending on the mutation type.
b.
In the intron?
Yes mutant site will be expected. It will be transcript-ed as well and it cannot be a polypeptide
c.
In the promoter?
Yes mutant site will be expected. It will not be transcript-ed and it cannot be a polypeptide
d.
In the intron-exon boundary?
Yes mutant site will be expected. It will be transcript-ed and it cannot be a polypeptide
It would be GCGATT. C always compliments G and A always compliments T in the case of DNA coding
From the data, the manatee population obviously increased after the regulations went into affect and the deaths due to watercraft reduced from 25 to 8 after the regulations were put into effect. The population increased by 165% from 1980=-2010 and the drop in deaths due to watercraft decreased by
68%.So this is not a direct correlation but at least it shows that the watercraft deaths decreased significantly. Since the population increased at a greater rate then it may be that more females were spared so could mate and give birth to that many more manatees.
Answer:
A Carries urine to the bladder
B excretes urine out of the body
C stores urine temporarily
D produce urine
Explanation:
