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STatiana [176]
3 years ago
15

You select a family with three children. It M represents a male child, and F represents a female child, the set of equally likel

y outcomes for the children's genders is (MMM, MIMF MFM, MFF, FMM, FMF, FFM, FFF ) Find the probability of selecting a family with fewer than 5 male children P(fewer than 5 male children) Type an integer or a simplified fraction.)
Mathematics
1 answer:
Afina-wow [57]3 years ago
4 0

Answer with explanation:

→If a Family has five children, then Total likely outcome can be represented as:

Five Male =1

Five Female =1

4 Male +1 Female =4

4 Female +1 Male =4

3 Male +2 Female =10

3 Female +2 Male =10

Total Possible Outcome

 =1+1+4+4+10+10

or

   =2×2×2×2×2

     =32

,i.e either a children can be a male or female.

→If all the five childrens are male , then in the family number of children fewer than 5 male children =32-1=31

→Probability of an Event

         =\frac{\text{Total favorable Outcome}}{\text{Total Possible Outcome}}                    

→→Probability of selecting a family with fewer than 5 male children

       =\frac{31}{32}

                                     

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