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belka [17]
2 years ago
11

A football team has attempted 6 running plays. The change in field position resulting from each play is shown in the table. Runn

ing Play Outcomes Play 1 –3 yards Play 2 2 yards Play 3 –1 yard Play 4 –2 yards Play 5 –3 yards Play 6 1 yard What is the average change in field position per running play? –6 yards per play –1 yard per play 0 yards per play 1 yard per play Mark this and return
Mathematics
1 answer:
Semenov [28]2 years ago
4 0

Answer:

Step-by-step explanation:

-3 +2 +-1 +-2 +-3 +1 = -6 yards total

-6 / 6 =  -1 yard per play average

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Can u help me with this
Art [367]

Answer:

6

Step-by-step explanation:

each tomato=4

7-4=3 so each avocado is 3

5-3=2 so each lime is two

so 4+2=6

3 0
2 years ago
Read 2 more answers
What is the solution to the equation 6x = 39?
SashulF [63]

Answer:

6.5

Step-by-step explanation:

39/6 comes out to 6.5

8 0
4 years ago
16 The cost for parking at a city airport is shown in the table.
Alexxx [7]

Answer:

He paid $9 twelve times

12× 2= 24 days

Step-by-step explanation:

1st day = $16.60

3rd day=$ 9 (i.e for every 2days afterwards)

5th day=$ 9

Yuri pays : 124.60

124.60-16.60

= $108.00

After paying the first day he paid 108.00

108.00÷ 9 = 12

He paid $9 twelve times

12× 2= 24 days

3 0
3 years ago
[4]
Tanya [424]

Answer:

Angle ACD = 38°

Step-by-step explanation:

The full, correct question is presented the attached image to this solution.

Given

Point O is the centre if the circle

Points A, B, C and D are points on the circle

Angle AOB = 140°

Angle OAC = 14°

Angle AOB = 2 × (Angle ACB) [angle subtended at the centre of the circle is twice the angle subtended at the circumference of the circle)

140° = 2 × (Angle ACB)

Angle ACB = (140°/2) = 70°

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180° [sun of angles in a triangle is 180°]

But Angle OAB = Angle ABO = a [base angles of an iscosceles triangle are equal since OA and OB are both radii for the circle O)

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180°

140° + a + a = 180°

2a = 40°

a = (40/2) = 20°

Angle OAB = Angle ABO = 20°

Angle CAB = (Angle OAC) + (Angle OAB) = 14° + 20° = 34°

Triangle ADC is an iscosceles triangle, hence,

Angle DAC = Angle ACD = x [base angles of an iscosceles triangle are equal]

But

(Angle DCB) + (Angle DAB) = 180° [Opposite angles of a cyclic quadilateral (a quadilateral inscribed in a circle) sum up to give 180°]

Angle DCB = (Angle DCA) + (Angle ACB) = (x + 70°)

Angle DAB = (Angle DAC) + (Angle CAB) = (x + 34°)

(Angle DCB) + (Angle DAB) = 180°

(x + 70°) + (x + 34°) = 180°

2x + 104° = 180°

2x = 180° - 104° = 76°

x = (76°/2) = 38°

Angle DAC = Angle ACD = 38°

Angle ACD = 38°

Hope this Helps!!!

7 0
3 years ago
Which situation can be modeled by the inequality 50 - 12x > 8?
eduard

Answer:

Option D.

Step-by-step explanation:

Borrowed $50 from your cousin. You pay him $8 and must pay him back within 12 weeks.

Let x be the amount paid on each week.

50-8\leq 12x

50-12x\leq 8

You can buy bags of pretzels in packages of 12. You $50 to spend, but want to have at least $8 left.

Let x be the amount of each package.

50-12x\geq 8

You owe your sister $50. You plan to pay her $12 a week till you owe her less than $8.

Let x be the amount paid on each week.

50-12x

You have $50 to spend on clothes, but you need to save at least $8 for bus fare. You plan to spend the rest on shirts that cost $12 each (including tax).

Let x be the number of shirts

50-12x>8

Therefore, the correct option is D.

7 0
3 years ago
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