Question

The mean on a standardized test is 100 and the standard deviation is 35. Your score is 65. What percentage of the scores were higher than yours?

Answer 1

Answer:

84.13%

Step-by-step explanation:

Given data:

mean μ= 100 and standard deviation= 35

P(x>65)=$P(z>\frac{\mu-\sigma}{\sigma})$

putting vales we get

P(z>(65-100)/35)=P(z>-1) or P(z<1).,

from normal distribution table we get

P(z<1)= 0.8413= 84.13%