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erma4kov [3.2K]
3 years ago
6

How many times does the equation f(x)=2x^2+9x-5 intersect the x-axis

Mathematics
1 answer:
Komok [63]3 years ago
8 0

Answer:

2

Step-by-step explanation:

f(x)=2x^2+9x-5

When we are find how many times it intersects the x axis, we are finding the zero's. Set the equation equal to zero

0=2x^2+9x-5

Factor the equation

0 = (2x+1) (x-5)

2*1

1*-5 = -5

2*-5 +1*1 = -9

This checks for the first last and middle terms so we factored correctly

Then using the zero product property

2x+1 = 0 and x-5 =0

2x = -1    x=5

x = -1/2  and x=5

This function crosses the x axis 2 times

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2 years ago
My watch is 5 minutes slow, but i think it is 3 minutes fast. I arrive 'on time' according to my calculations to catch the 1:15
faltersainse [42]
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3 years ago
Find a numerical value of one trigonometric function of x for cscx = sinx tanx + cosx
Alex787 [66]

Answer:

Step-by-step explanation:

we have

cscx = sinx tanx + cosx\\\\\frac{1}{sinx}=sinx.\frac{sinx}{cosx} +cosx\\\\\frac{1}{sinx}.sinx.cosx= sinx.\frac{sinx}{cosx}.sinx.cosx+cosx.sinx.cosx\\  cosx= (sinx)^{3} +sinx.(cosx)^{2} \\cosx= sinx[(sinx)^{2}+(cosx)^{2})\\  cosx=sinx.1\\cosx=sinx\\tanx=1\\x=\frac{\pi}{4} +k\pi,k-integer.

6 0
2 years ago
Factor Trinomials (a=1)<br> factor <br><br> x^2-10x+16
dem82 [27]

Answer:

(x-8)(x-2)

Step-by-step explanation:

factors of 16:

1 x 16

2 x 8

4 x 4

i'll select 2 and 8 as values because they can add up to 10

(x-8)(x-2)

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8 0
2 years ago
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Hoochie [10]

Answer:

-3(r-2)/2

Step-by-step explanation:

r/ 2 − 2 r + 6 − 3

r /2 − 2 r⋅ 2/ 2+ 6 − 3

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r − 2 r ⋅ 2 /2 + 6 ⋅ 2/ 2 + − 3 ⋅ 2/ 2

r − 2 r ⋅2 + 6⋅ 2 − 3 ⋅ 2 /2

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−3 ( r − 2 ) /2

Hope that helps! Plz, mark brainiest! :D

Have a great day!

7 0
2 years ago
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