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Elenna [48]
3 years ago
6

What is the area of a rectangular playground with a length of 24 feet and a width of 18 feet?

Mathematics
2 answers:
vazorg [7]3 years ago
7 0

Answer:

area of a rectangular field = 432feet²

Step-by-step explanation:

area of a rectangular field = ?

length of the rectangular field = 24feet

width of the rectangular field = 18feet

recall that, the formulae for finding the area of a rectangle

=width x length

area of a rectangular field = 24feet x 18feet

area of a rectangular field = 432feet²

therefore the area of a rectangular playgroud  whose length is 24 feet and

18width is evaluated to be 432feet²

maw [93]3 years ago
6 0

Answer: 432

Step-by-step explanation:

Multiply your length times your width to get the area.

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Evaluate the expression 2v^3•v^0
alekssr [168]

Answer:

2v^3

Step-by-step explanation:

hope it helps ;)

6 0
3 years ago
Please answer I need help asap
strojnjashka [21]

Answer:

x=5

Step-by-step explanation:

\frac{x}{3} =\frac{9+6}{9} \\\\\frac{x}{3} =\frac{15}{9}

cross multiply

45=9x

solve for x by dividing 9 to get x alone

5=x

6 0
3 years ago
Read 2 more answers
Could I get some help?
balandron [24]

Answer:

#adult tickets sold = 346

#student tickets sold = 812

Step-by-step explanation:

let 'x' = # adult tickets sold

let 'y' = # students tickets sold

System of Equations:

x + y = 1158

5x + y = 2542

I used the elimination method and multiplied the first equation by -1

  -x - y = -1158

+<u> 5x + y = 2542</u>

  4x  =  1384

   x = 346

346 + y = 1158

y = 812

4 0
3 years ago
Find the missing value.-7/13 = m/104
exis [7]

<em>answer = - 56  \\ solution \\  \frac{ - 7}{13}  =  \frac{m}{104}  \\ or \: 13 \times m = 104 \times ( - 7) \\ or \: 13 \: m =  - 728 \\ or \: m =  \frac{ - 728}{13}  \\ m = -  56 \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment</em>

8 0
3 years ago
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5. Find the value(s) of x so that the line containing the points (2x + 3, x + 2) and (0, 2) is
Dvinal [7]

Answer:

  x = -2 or -9

Step-by-step explanation:

You want the values of x such that the line defined by the two points (2x+3, x+2) and (0, 2) is perpendicular to the line defined by the two points (x+2, -3-3x) and (8, -1).

<h3>Slope</h3>

The slope of a line is given by the slope formula:

  m = (y2 -y1)/(x2 -x1)

Using the formula, the slopes of the two lines are ...

  m1 = (2 -(x+2))/(0 -(2x+3)) = (-x)/(-2x-3) = x/(2x +3)

and

  m2 = (-1 -(-3-3x))/(8 -(x+2)) = (2+3x)/(6 -x)

<h3>Perpendicular lines</h3>

The slopes of perpendicular lines have product of -1:

  \dfrac{x}{2x+3}\cdot\dfrac{2+3x}{6-x}=-1\\\\x(3x+2)=(2x+3)(x-6)\qquad\text{multiply by $(2x+3)(6-x)$}\\\\3x^2+2x=2x^2-9x-18\qquad\text{eliminate parentheses}\\\\x^2+11x+18=0\qquad\text{put in standard form}\\\\(x+2)(x+9)=0\qquad\text{factor}

<h3>Solutions</h3>

The values of x that satisfy this equation are x = -2 and x = -9. The attached graphs show the lines for each of these cases.

4 0
1 year ago
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