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2 years ago

When x = 6 and y = 3, which of the expressions below will be greater than 100? Select all

Mathematics

1 answer:

AlladinOne [14]2 years ago

5 0

I think it would be c

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Heeeelp just need 1 and 3

Harlamova29_29 [7]

Answer: I think the answer is. x=y*z I dont know what the verbles are but thats what I got. ANd can you zoom in a bit?

Step-by-step explanation:

4 0

2 years ago

Expand and simplify 4 ( y + 6 ) − 2 ( y − 2 )

elena-14-01-66 [18.8K]

[ Answer ]

$\boxed{2y \ + \ 28}$

[ Explanation ]

4(y + 6) - 2(y - 2)

[Expand] 4(y + 6): 4y + 24

4y + 24 - 2(y - 2)

[Expand] -2(y - 2): -2y + 4

4y + 24 - 2y + 4

[Simplify] 4y + 24 - 2y + 4: 2y + 28

= 2y + 28

$\boxed{[ \ Eclipsed \ ]}$

7 0

3 years ago

Read 2 more answers

-1/3 -(-5/12) which shows an equivalent addition expression

dem82 [27]

Answer:

-1/3 - (-5/12) = 1/12.

Step-by-step explanation:

Simpler equation:

6/12 + (-5/12) = 1/12

Or This:

6/12 - 5/12 = 1/12.

hope this helped.

5 0

2 years ago

The manager wants to advertise that anybody who isn't served within a certain number of minutes gets a free hamburger. But she d

aksik [14]

Answer:

The number of minutes advertisement should use is found.

x ≅ 12 mins

Step-by-step explanation:

(MISSING PART OF THE QUESTION: AVERAGE WAITING TIME = 2.5 MINUTES)

For such problems, we can use probability density function, in which probability is found out by taking integral of a function across an interval.

Probability Density Function is given by:

$f(t)=\left \{ {{0 ,\-t$

Consider the second function:

$f(t)=\frac{e^{-t/\mu}}{\mu}\\$

Where Average waiting time = μ = 2.5

The function f(t) becomes

$f(t)=0.4e^{-0.4t}$

The manager wants to give free hamburgers to only 1% of her costumers, which means that probability of a costumer getting a free hamburger is 0.01

The probability that a costumer has to wait for more than x minutes is:

$\int\limits^\infty_x {f(t)} \, dt= \int\limits^\infty_x {}0.4e^{-0.4t}dt$

which is equal to 0.01

Solve the equation for x

$\int\limits^{\infty}_x {0.4e^{-0.4t}} \, dt =0.01\\\\\frac{0.4e^{-0.4t}}{-0.4}=0.01\\\\-e^{-0.4t} |^\infty_x =0.01\\\\e^{-0.4x}=0.01$

Take natural log on both sides

$ln (e^{-0.4x})=ln(0.01)\\-0.4x=ln(0.01)\\-0.4x=-4.61\\x= 11.53$

<h3>Results</h3>

The costumer has to wait x = 11.53 mins ≅ 12 mins to get a free hamburger

3 0

2 years ago

Nicholas has 8 pieces of rope that are 4 yards each. He uses 4 pieces that are each 4 feet long.

Komok [63]

What's the question nbnnbbb

4 0

3 years ago