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GalinKa [24]
3 years ago
9

GEOMETRY

Mathematics
1 answer:
iris [78.8K]3 years ago
5 0
I would say c I think
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Answer: Hewo, there! your answer is Below.

B.

linear Would be my answer because it's arranged in or extending along a straight or nearly straight line.

Step-by-step explanation:

Hope this helps!!

have a great day!!!]

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What is the coefficient of x in 2x+3?<br><br>Please answer?
DaniilM [7]

Answer:

coefficient of x is 2

Step-by-step explanation:

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Write the expression of seven less than n
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7 < n, what you do is take the number figure out whether or not its bigger or smaller, add in the sign, and put your n or variable (:
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I need questions number 4 and 6
ludmilkaskok [199]

Answer:

4) p=b(1/2)

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Step-by-step explanation:

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3 years ago
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Suppose you know the length of a confidence interval of a population mean is 8.4 and the sample mean (x bar) is 10. Find the ​ma
SOVA2 [1]

Answer:

ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

The lenght of the interval correspond to:

8.4 = 2ME

ME= \frac{8.4}{2}= 4.2

And since we know the margin of error we can find the limits for the confidence interval:

Lower = 10 -4.2=5.8

Upper = 10 +4.2=14.2

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

\bar X=10 represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n represent the sample size  

Solution to the problem

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma)

The sample mean \bar X is distributed on this way:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})  

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

The margin of error is given by:

ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

The lenght of the interval correspond to:

8.4 = 2ME

ME= \frac{8.4}{2}= 4.2

And since we know the margin of error we can find the limits for the confidence interval:

Lower = 10 -4.2=5.8

Upper = 10 +4.2=14.2

4 0
3 years ago
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