Hello there.
<span>The function f(x)=60(1.5)x models an animal population after x years.
How does the average rate of change between Years 3 and 6 compare to the average rate of change between Years 0 and 3?
</span><span>The average rate of change is 3.375 times as fast.</span>
Answer:
(x+5)^2
Step-by-step explanation:
(x+5)^2 Using the foil method 5+5=10 and 5x5=25
Answer:
7. 25 and 8. 18. I think it is. I hoped that is was right.
Step-by-step explanation:
150/6=25. 90/5=18.
Answer:
15/20
Step-by-step explanation:
It is the only one that can be simplified into 3/5
Amount of money spent on pass and lunch of each student is 28.56 Dollars.
Step-by-step explanation:
Amount spend by school in passes = 868.48 dollars
Total number of students and teachers = 44+2 = 46
Amount spend on one pass = 

Amount spend on lunch= 425.92 dollars
Amount spend on one lunch = 

For calculating amount of lunch and pass for each student we will add the amounts;
Each student costed = Each lunch amount + Each pass amount
Total money for one student = 
Total money for one student = 28.56 Dollars
Amount of money spent on pass and lunch of each student is 28.56 Dollars.
Keywords: Division, Addition.
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