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sergejj [24]
3 years ago
8

Can Someone Help Me With This

Mathematics
1 answer:
igomit [66]3 years ago
5 0
Ok imma not sure exactly how you would put this in but this is the answer:

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If f(x)= 15x+7x and g(x)= x^2-5x, find (f+g)(x)
cupoosta [38]

Answer:

(f+g)(x) = x^2 +10x +7

Step-by-step explanation:

(f+g)(x) = f(x) +g(x) = (15x +7) +(x^2 -5x)

= x^2 +x(15 -5) +7

= x^2 +10x +7

7 0
3 years ago
Find the logarithmic function y = logbx that passes through the points
katovenus [111]

b\in(0,\ 1)\ \cup\ (1,\ \infty)\\x > 0\\y\in\mathbb{R}\\--------------------------\\\\y=\log_bx\\\\For\ (1,\ 0)\to x=1,\ y=0.\ Substitute:\\\\\log_b1=0\to b^0=1\to b\in(0,\ 1)\ \cup\ (1,\ \infty)\\\\For\ (116,\ 2)\to x=116,\ y=2.\ Substitute:\\\\\log_b116=2\to b^2=116\to b=\sqrt{116}\\\to b=\sqrt{4\cdot29}\to b=\sqrt4\cdot\sqrt{29}\to b=2\sqrt{29}\\\\For\ (4,\ -1)\to x=4,\ y=-1.\ Substitute:\\\\\log_b4=-1\to b^{-1}=4\to b=\dfrac{1}{4}

Different values of b.

<h3>Answer: There is no logarithmic function whose graph goes through given points.</h3><h3 />

Maybe the second point is \left(\dfrac{1}{16},\ 2\right)

Substitute:

\log_b\dfrac{1}{16}=2\to b^2=\dfrac{1}{16}\to b=\sqrt{\dfrac{1}{16}}\to b=\dfrac{1}{4}

<h3>Then we have the answer:</h3>

\boxed{y=\log_{\frac{1}{4}}x}

6 0
3 years ago
Help is really needed!
RideAnS [48]

Answer:

The First table is going by 6 on the top, the bottom is going by 1.5.

<u>  6          12          18          24</u>

1.5          3          4.5           6

The Second table is going by multiplying by 2 on the top, the bottom is doing the same thing(from least to greatest).

<u>112.8          56.4          28.2          14.1 </u>

5,640      2,820         1,140          570

The cost per pound of apples on sale is $1.50.

3÷2= 1.50

You can buy 12 pounds of apples for $18.00.

18.00÷1.5= 12

Since 1 pound=16 ounces, so there are about 3 apples in each pound.

16÷5= 3.2

You can buy approximately 36 apples with $18.00.

12×3= 36

8 0
3 years ago
Simplify the expression (3+8i) - (4+2i) pls show work!
uranmaximum [27]

Subtract like terms:

3 -4 = -1

8i - 2i = 6i

The answer is -1+6i

3 0
3 years ago
Co-ordinate Geometry
saul85 [17]

Answer:

The value of a  = 14

Step-by-step explanation:

Given

(x₁, y₁) = (2, 4)

(x₂, y₂) = (6, a)

(x₃, y₃) = (-1, 1)

A = 9 sq.units

Area of a triangle with vertices (x₁, y₁), (x₂, y₂), and (x₃, y₃) is:

A=\frac{\left|x_1\left(y_2-y_3\right)+x_2\left(y_3-y_1\right)+x_3\left(y_1-y_2\right)\right|}{2}

substituting the values (x₁, y₁) = (2, 4), (x₂, y₂) = (6, a), (x₃, y₃) = (-1, 1), A = 9 in th formula

A=\frac{\left|x_1\left(y_2-y_3\right)+x_2\left(y_3-y_1\right)+x_3\left(y_1-y_2\right)\right|}{2}

9=\frac{\left|2\left(a-1\right)+6\left(1-4\right)+-1\left(4-a\right)\right|}{2}

Multiply both sides by 2

\frac{2\left|2\left(a-1\right)+6\left(1-4\right)-1\left(4-a\right)\right|}{2}=9\cdot \:2

simplify

\left|2\left(a-1\right)+6\left(1-4\right)-1\left(4-a\right)\right|=18

As the area is always positive.

so

2\left(a-1\right)+6\left(1-4\right)-1\cdot \left(4-a\right)=18

2\left(a-1\right)-18-\left(4-a\right)=18

Add 18 to both sides

2\left(a-1\right)-18-\left(4-a\right)+18=18+18

simplify

2\left(a-1\right)-\left(4-a\right)=36

3a-6=36

3a=42

Divide both sides by 3

\frac{3a}{3}=\frac{42}{3}

a=14

Thus, the value of a  = 14

7 0
3 years ago
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