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3 years ago

Can Someone Help Me With This

Mathematics

1 answer:

igomit [66]3 years ago

5 0

Ok imma not sure exactly how you would put this in but this is the answer:

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If f(x)= 15x+7x and g(x)= x^2-5x, find (f+g)(x)

cupoosta [38]

Answer:

(f+g)(x) = x^2 +10x +7

Step-by-step explanation:

(f+g)(x) = f(x) +g(x) = (15x +7) +(x^2 -5x)

= x^2 +x(15 -5) +7

= x^2 +10x +7

7 0

3 years ago

Find the logarithmic function y = logbx that passes through the points

katovenus [111]

$b\in(0,\ 1)\ \cup\ (1,\ \infty)\\x > 0\\y\in\mathbb{R}\\--------------------------\\\\y=\log_bx\\\\For\ (1,\ 0)\to x=1,\ y=0.\ Substitute:\\\\\log_b1=0\to b^0=1\to b\in(0,\ 1)\ \cup\ (1,\ \infty)\\\\For\ (116,\ 2)\to x=116,\ y=2.\ Substitute:\\\\\log_b116=2\to b^2=116\to b=\sqrt{116}\\\to b=\sqrt{4\cdot29}\to b=\sqrt4\cdot\sqrt{29}\to b=2\sqrt{29}\\\\For\ (4,\ -1)\to x=4,\ y=-1.\ Substitute:\\\\\log_b4=-1\to b^{-1}=4\to b=\dfrac{1}{4}$

Different values of b.

<h3>Answer: There is no logarithmic function whose graph goes through given points.</h3><h3 />

Maybe the second point is $\left(\dfrac{1}{16},\ 2\right)$

Substitute:

$\log_b\dfrac{1}{16}=2\to b^2=\dfrac{1}{16}\to b=\sqrt{\dfrac{1}{16}}\to b=\dfrac{1}{4}$

<h3>Then we have the answer:</h3>

$\boxed{y=\log_{\frac{1}{4}}x}$

6 0

3 years ago

Help is really needed!

RideAnS [48]

Answer:

The First table is going by 6 on the top, the bottom is going by 1.5.

1.5 3 4.5 6

The Second table is going by multiplying by 2 on the top, the bottom is doing the same thing(from least to greatest).

5,640 2,820 1,140 570

The cost per pound of apples on sale is $1.50.

3÷2= 1.50

You can buy 12 pounds of apples for $18.00.

18.00÷1.5= 12

Since 1 pound=16 ounces, so there are about 3 apples in each pound.

16÷5= 3.2

You can buy approximately 36 apples with $18.00.

12×3= 36

8 0

3 years ago

Simplify the expression (3+8i) - (4+2i) pls show work!

uranmaximum [27]

Subtract like terms:

3 -4 = -1

8i - 2i = 6i

The answer is -1+6i

3 0

3 years ago

Co-ordinate Geometry

saul85 [17]

Answer:

The value of a = 14

Step-by-step explanation:

Given

(x₁, y₁) = (2, 4)

(x₂, y₂) = (6, a)

(x₃, y₃) = (-1, 1)

A = 9 sq.units

Area of a triangle with vertices (x₁, y₁), (x₂, y₂), and (x₃, y₃) is:

$A=\frac{\left|x_1\left(y_2-y_3\right)+x_2\left(y_3-y_1\right)+x_3\left(y_1-y_2\right)\right|}{2}$

substituting the values (x₁, y₁) = (2, 4), (x₂, y₂) = (6, a), (x₃, y₃) = (-1, 1), A = 9 in th formula

$A=\frac{\left|x_1\left(y_2-y_3\right)+x_2\left(y_3-y_1\right)+x_3\left(y_1-y_2\right)\right|}{2}$

$9=\frac{\left|2\left(a-1\right)+6\left(1-4\right)+-1\left(4-a\right)\right|}{2}$

Multiply both sides by 2

$\frac{2\left|2\left(a-1\right)+6\left(1-4\right)-1\left(4-a\right)\right|}{2}=9\cdot \:2$

simplify

$\left|2\left(a-1\right)+6\left(1-4\right)-1\left(4-a\right)\right|=18$

As the area is always positive.

$2\left(a-1\right)+6\left(1-4\right)-1\cdot \left(4-a\right)=18$

$2\left(a-1\right)-18-\left(4-a\right)=18$

Add 18 to both sides

$2\left(a-1\right)-18-\left(4-a\right)+18=18+18$

simplify

$2\left(a-1\right)-\left(4-a\right)=36$

$3a-6=36$

$3a=42$

Divide both sides by 3

$\frac{3a}{3}=\frac{42}{3}$

$a=14$

Thus, the value of a = 14

7 0

3 years ago