Answer: 
Step-by-step explanation:
Given
The area is bounded by
and x-axis from [0,2]
The volume generated for
when rotated about the x-axis in the interval [a,b] is

Insert the values
![\Rightarrow V=\int_0^2\pi x^4dx\\\\\Rightarrow V=\pi \int_0^2x^4dx\\\\\Rightarrow V=\pi \left[ \dfrac{x^5}{5}\right]_0^2\\\\\Rightarrow V=\dfrac{2^5\pi }{5}\\\\\Rightarrow V=\dfrac{32\pi }{5}\ \text{unit}^3](https://tex.z-dn.net/?f=%5CRightarrow%20V%3D%5Cint_0%5E2%5Cpi%20x%5E4dx%5C%5C%5C%5C%5CRightarrow%20V%3D%5Cpi%20%5Cint_0%5E2x%5E4dx%5C%5C%5C%5C%5CRightarrow%20V%3D%5Cpi%20%5Cleft%5B%20%5Cdfrac%7Bx%5E5%7D%7B5%7D%5Cright%5D_0%5E2%5C%5C%5C%5C%5CRightarrow%20V%3D%5Cdfrac%7B2%5E5%5Cpi%20%7D%7B5%7D%5C%5C%5C%5C%5CRightarrow%20V%3D%5Cdfrac%7B32%5Cpi%20%7D%7B5%7D%5C%20%5Ctext%7Bunit%7D%5E3)
Answer: A)
Step-by-step explanation:
In a biconditonal statement the output is true if at least one input is true….this is false.
Answer:
35.03% probability that fewer than 7 will be carrying backpacks
Step-by-step explanation:
For each student, there are only two possible outcomes. Either they are carrying a backpack, or they are not. The probability of a student carrying a backpack is independent from other students. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
The probability that an Oxnard University student is carrying a backpack is .70.
This means that 
If 10 students are observed at random, what is the probability that fewer than 7 will be carrying backpacks
This is
when
. So










35.03% probability that fewer than 7 will be carrying backpacks
Answer:
Using a graphing calc.
Step-by-step explanation: