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3 years ago

Science help required!

Biology

2 answers:

Ierofanga [76]3 years ago

6 0

6 is ecosystem is the correct answer

Butoxors [25]3 years ago

4 0

Answer:

6 is ecosystem 8 is organism and 9 is c i think

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A woman is heterozygous for the CF-associated gene (the alleles are represented here by the letters A and a). Assuming that meio

harkovskaia [24]

Answer:

The correct answer is C.

Explanation:

In the question, it is stated that the woman is heterozygous, which means she posseses both the dominant allele and the recessive allele (A and a). So taking this information into account, she can produce eggs given with the option C (Aa) which include both the dominant and recessive alleles.

I hope this answer helps.

4 0

3 years ago

When pink sweet peas were self-pollinated and the seeds were collected and sown, the following flower colors were obtained: Red

Pavlova-9 [17]

Answer:

c. 1:2:1

The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.

Explanation:

If flower color were determined by a gene showing incomplete dominance, the possible genotypes and phenotypes are as follows:

RR- red
ww - white
Rw - pink

If pink sweet peas are self-pollinated, then a cross between two heterozygous individuals is done (Rw x Rw).

From this cross the expected ratios are:

1/4 RR (red)
2/4 Rw (pink)
1/4 ww (white)

So the null hypothesis is that the observed results exhibit a 1:2:1 ratio.

<h3>Chi square test</h3>

$X^{2} = \sum \frac{(Observed - Expected)^2}{Expected}$

The observed frequencies were:

34 Red
76 Pink
40 White

Total 150

The expected frequencies for our null hypothesis are:

1/4 x 150 = 37.5 Red
2/4 x 150 = 75 Pink
1/4 x 150 = 37.5 white

$X^{2} = \frac{(34- 37.5)^2}{37.5} + \frac{(76- 75)^2}{75} + \frac{(40- 37.5)^2}{37.5}$

$X^2=0.5067$

The degrees of freedom (DF) are calculated as number of phenotypes - 1; in this case DF = 3-1 = 2.

If we look at the Chi square table, for 2 DF and a probability of p0.05, the critical value is 5.991

Our X^2 value of 0.5067 is less than the critical value, so we do not reject the null hypothesis. The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.

8 0

3 years ago

Which explanation justifies why the theory of evolution is a theory and not a law? (4 points) a The theory of evolution predicts

Lyrx [107]

Answer:d.Additional evidence will change the theory of evolution into a law.

Explanation:

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2 years ago

Which answer is not a mechanism for evolution? Genetic Drift Mutations Gene pool Natural Selection

lawyer [7]

Genetic drift I think

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2 years ago

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Explain how critical value variations influence statistical power.

zloy xaker [14]

Statistical power is the likelihood that a test (statistical test) will detect an effect when there is an effect there to be detected. Statistical power is inversely related to the probability of making a Type II error (Type II errors, or false negatives, occur when you don’t see things that are there) = beta.
statistical power = 1 – β. The critical value is the value corresponding to a given significance level. The statistical power is influenced by the choice of significance level for the test (by the critical value). Larger critical value means increased power of the test: the chance of obtaining a statistically significant result is increased (reduces the risk of a Type II error (false negative regarding whether an effect exists) is reduced) .

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3 years ago

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