The quadratic formula can be used to solve an equation only if the highest

ryan earns $5 for each small dog he walks and $8 for each latge dog he walks. today he walked 8 dogs and made a total of $55. ho

ad-work [718]

If we divide 55 (the total amount of money he made) by 5 (price to walk one small dog), we get 11. Meaning that the maximum amount of small dogs he could possibly walk and receive that amount of money is 11. However, he only walked 8 dogs. Therefore Ryan would have needed to walk a specific amount of large dogs in order to earn 55 dollars in total.

After doing some process of elimination, I reached this conclusion:

3 small dogs = $15

5 large dogs = $40

The combination of the two would equal $55.

Therefore, the answer would be 3 small dogs.

7 0

4 years ago

Based on the Nielsen ratings, the local CBS affiliate claims its 11:00 PM newscast reaches 41 % of the viewing audience in the a

ZanzabumX [31]

Answer:

1) Null hypothesis: $p\geq 0.41$

Alternative hypothesis: $p < 0.41$

2) $\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

3) $z_{crit}=-2.33$

And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

4) $z=\frac{0.36 -0.41}{\sqrt{\frac{0.41(1-0.41)}{1000}}}=-1.017$

5) $z_{crit}=-1.28$

And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"

6) We see that $|t_{calculated}|$ so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.

7) Null hypothesis: $p\geq 0.41$

Step-by-step explanation:

Data given and notation

n=100 represent the random sample taken

X represent the people indicated that they watch the late evening news on this local CBS station

$\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

$p_o=0.41$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v{/tex} represent the p value (variable of interest) Part 1We need to conduct a hypothesis in order to test the claim that 11:00 PM newscast reaches 41 % of the viewing audience in the area: Null hypothesis:[tex]p\geq 0.41$

Alternative hypothesis: $p < 0.41$

Part 2

$\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

Part 3

Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.01 of the area on the left and on this case this value is :

$z_{crit}=-2.33$

And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

Part 4

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.36 -0.41}{\sqrt{\frac{0.41(1-0.41)}{1000}}}=-1.017$

Part 5

Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.1 of the area on the left and on this case this value is :

$z_{crit}=-1.28$

And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"

Part 6

We see that $|t_{calculated}|$ so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.

Part 7

Null hypothesis: $p\geq 0.41$

4 0

3 years ago

A right triangle has legs that measure 7 cm and 6 cm. What is the length of the hypotenuse in meters?

dalvyx [7]

<h2>Greetings!</h2>

Answer:

$\sqrt{85} or 9.22$

Step-by-step explanation:

You need to remember the following equation:

$a^{2} + b^{2} = c^{2}$

Where a and b is the lengths of the two sides and c is the hypotenuse.

So simply plug these values into this:

$6^{2} + 7^{2} = h^{2}$

36 + 49 = h^2

36 + 49 = 85

So the hypotenuse is the square root of 85:

$\sqrt{85} = 9.22$

<h2>Hope this helps!</h2>

7 0

3 years ago

Examine the system of equations.

Pachacha [2.7K]

Step-by-step explanation:

The lines have different slopes

.......,............

6 0

3 years ago

Please help find the anwser to question 1 and 2

grin007 [14]

16ft and 25ft sorry if i’m wrong

4 0

3 years ago