Direct variations take the form y=kx. We need to solve for y in order to find k.
<span>3x+5y=0 </span>
<span>5y=-3x </span>
<span>y=(-3/5)*x </span>
<span>k=-3/5.</span>
Answer: c) -4
Step-by-step explanation:
Get the variables on one side of 3x+y=-2x+8 and the constants on another side:
3x+y=-2x+8
(3x+y)+2x=(-2x+8)+2x
5x+y=8
Now, multiply 5x+y=8 by -2:
-2(5x+y=8)
-10x-2y=-16
Add this equation to -3x+2y=-10:
(-10x-2y=-16)+(-3x+2y=-10)
-13x=-26
x=2
Plug x=2 into -3x+2y=-10:
-3(2)+2y=-10
-6+2y=-10
2y=-4
y=-2
Therefore, (2, -2) is the solution to the system of equations, so xy=(2)(-2)=-4
Hi pupil here's your answer ::
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✴A triangle cannot have three acute angles
✔This statement is absolutely true.
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hope that it helps. . . . .
Answer:
all real numbers
Step-by-step explanation:
The graphs of positive and negative x^2 parabolas will always have a domain of all real numbers. Even though you only have a portion of the graph and see a "restriction" on your domain values, it is incorrect to assume that the domain is limited to what you can see. As the branches of the parabola keep going up and up and up, the values of x keep getting bigger and bigger and bigger. Again, this is true for all + or - parabolas. ....... Can consider brainlist*:)
