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Elena-2011 [213]
3 years ago
12

Question Progress

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
5 0

The two numbers are 3 and 18, if the sum of two number is 21 and the second number is six times the first number.

Step-by-step explanation:

The given is,

                  The sum of two numbers is 21

                   The second number is six times the first number

Step:1

          Let, m - First number

                  n - Second number

Step:2

        From given,

                  n - 6m     ( The second number is six times the first number )

        Equation becomes,

                  Sum = m + n

        Where,

                      21 = m + ( 6m )

                       21 = 7m

                       m = 3

        Substitute m value n becomes,

                        n = 6m

                           = (6 × 3)

                      n  = 18

Result:

          The two numbers are 3 and 18, if the sum of two number is 21 and the second number is six times the first number.

                   

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Consider this sphere inside the cylinder. Which statements are true? Check all that apply. NEED HELP ASAP​
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Option C: The radius of the sphere is half the height of the cylinder.

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Solution:

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Option A: The height of the cylinder is equal to the diameter of the sphere.

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Option B: The height of the cylinder is two times the diameter of the sphere.

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Option C: The radius of the sphere is half the height of the cylinder.

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Substitute d = 2r, we get

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Divide by 2 on both sides, we get

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Option D: The diameter of the sphere is equal to the radius of the cylinder.

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Height of cylinder h = 2r (by option C)

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$\Rightarrow \pi r^2 (2r) = \frac{2\times2}{3} \pi r^3

$\Rightarrow 2 \pi r^3= \frac{2}{3} \times 2\pi r^3

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