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4 years ago

The graph of which function has an axis of symmetry at x = 3?

Mathematics

2 answers:

xz_007 [3.2K]4 years ago

5 0

f(x) = x² - 6x - 1

To find the axis of symmetry, use the axis of symmetry formula: -b\2a, according to the Quadratic Equation y = Ax² + Bx + C. You understand?

Nata [24]4 years ago

5 0

Answer:

$f(x) = x^2 - 6x -1$

Step-by-step explanation:

To find axis of symmetry we use formula

$x=\frac{-b}{2a}$

$f(x) = x^2 + 3x +1$

a=1, b=3

$x=\frac{-3}{2}$

$f(x) = x^2 -3x - 3$

a=1, b=-3

$x=\frac{3}{2}$

$f(x) = x^2 + 6x + 3$

a=1, b=6

$x=\frac{-6}{2}=-3$

$f(x) = x^2 - 6x -1$

a=1, b=-6

$x=\frac{6}{2}=3$

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Answer:

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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4 years ago

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2 years ago

Write a polynomial in standard form that meets the following conditions. Assume a=1 and your function is f(x), The zeros are 5 a

jeka57 [31]

Polynomials are equations that uses variables and several terms

The polynomial in standard form is f(x) = x^2 - x -20

<h3>How to determine the polynomial</h3>

The polynomial has 2 zeros.

So, the form of the polynomial is:

f(x) = a(x - x1)(x - x2)

The zeros of the polynomial are 5 and -4.

So, the equation becomes

f(x) = a(x - 5)(x + 4)

The value of a = 1.

So, we have;

f(x) = 1(x - 5)(x + 4)

This gives

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Expand

f(x) = x^2 - x -20

Hence, the polynomial in standard form is f(x) = x^2 - x -20