3 years ago

Find the total surface area of the composite figure. Round to the nearest tenth.

Mathematics

1 answer:

lara [203]3 years ago

7 0

I think the answer is 4.8

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Snow Crest is 11,508.21 feet higher than Mt. Wilson. Write and solve an equation to find the elevation of Mt. Wilson. Let x repr

Viefleur [7K]

Answer:

16642.1 feets

Step-by-step explanation:

Given :

Elevation of Mt. Wilson = x

If the elevation of snow crest = y

Snow crest = 11,508.21 feet higher than Mt. Wilson

Hence, y = 11,508.21 + x

The elevation of Mt. Wilson, x = y - 11,508.21 feets

From the table, elevation of Snow crest = 28,150.31 feets = y

Hence, The elevation of Mt. Wilson, x = y - 11,508.21 feets

x = 28,150.31 - 11,508.21

x = 16642.1 feets

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3 years ago

Solve the equation r/-4=-15

torisob [31]

Answer:

60/-4

Step-by-step explanation:

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3 years ago

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7000milimeters equals how many cm ?

matrenka [14]

1 cm equals to 10 mm, therefore 7000 mm = 700 cm.

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3 years ago

Can you work out 1/8 of 560?

damaskus [11]

Multiply 1/8 by 560
answer: 70

7 0

3 years ago

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two square regions have an area of 125 and 5 how many yards of fencing is needed to enclose? ( assume regions fenced separately)

nadya68 [22]

Answer:

$24\sqrt{5}\ yards$

Step-by-step explanation:

Let A1 be the area of one square and A2 be the area of second square

So,

A1 = s^2

where s is side of square

$s^2=125\\\sqrt{s^2}=\sqrt{125}\\s=\sqrt{25*5}\\ s= \sqrt{5^2 * 5}\\ s= 5\sqrt{5}$

So side of one square is $5\sqrt{5}$

To calculate the length of fence we need to find the perimeter of the square

So,

P1 = 4 * s

$=4*5\sqrt{5} \\=20\sqrt{5}$

For second square:

$A_2=s^2\\5=s^2\\\sqrt{s^2}=5\\{s}=\sqrt{5}$

The perimeter will be:

$P_2 = 4*s\\=4 * \sqrt{5} \\=4\sqrt{5}$

So the total fence will be: P1+P2

$= 20\sqrt{5}+4\sqrt{5} \\= 24\sqrt{5}\ yards$

3 0

3 years ago