5+2(3x-4)=12x-11 is 5+6x -8 = 12x -11, 5-8+11= 12x-6x, “8= 6x” so option B is correct
To do this make x and y equal 0, y-intercept is at x=0, and x-intercept is at y=0:
x-intercept:
2x+7(0) = -14
2x = -14
x = -7
y-intercept:
2(0) + 7y = -14
7y = -14
y = -2
Answer:
put one point b the negative -1 and another point by the 2 going long ways ------
Step-by-step explanation:
