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Ivenika [448]
3 years ago
14

Determine the followingquadratic equations have realroots1) 3x² - √2x-√3​

Mathematics
1 answer:
IceJOKER [234]3 years ago
3 0

Step-by-step explanation:

√3 x² - 2x - √3 = 0

√3 x² - 3x + x - √3 = 0

√3 x(x - √3) + 1(x - √3) = 0

(x - √3 ) (√3 x + 1) = 0

x - √3 = 0 , √3 x +1 = 0

x = √3 , x = -1/√3

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The area of the base of a prism is 21 cm2. The perimeter of the base is 20 cm. The height of the prism is 8 cm.
mart [117]
The lateral area of the prism equals to height * perimeter of the base. So the lateral area is 160 cm2. And the surface area of the prism equals to the area of the base*2+the lateral area= 202 cm2.
7 0
4 years ago
10. You used 8 cups of sugar while baking three dozen cookies and one cake. If you used 1.25 cups of sugar for the cake and the
DanielleElmas [232]

Answer:

I got 5.65

Step-by-step explanation:

36/8= 4.5,  4.5 +1.25= 5.65

8 0
3 years ago
Area of a triangle with points at (-9,5), (6,10), and (2,-10)
Ann [662]
First we are going to draw the triangle using the given coordinates. 
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Distance from point A to point B:
d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}
d_{AB}= \sqrt{(6+9)^2+(10-5)^2}
d_{AB}= \sqrt{(15)^2+(5)^2}
d_{AB}= \sqrt{225+25}
d_{AB}= \sqrt{250}
d_{AB}=15.81

Distance from point A to point C:
d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}
d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}
d_{AC}= \sqrt{11^2+(-15)^2}
d_{AC}= \sqrt{121+225}
d_{AC}= \sqrt{346}
d_{AC}= 18.60

Distance from point B from point C
d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}
d_{BC}= \sqrt{(-4)^2+(-20)^2}
d_{BC}= \sqrt{16+400}
d_{BC}= \sqrt{416}
d_{BC}=20.40

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
s= \frac{AB+AC+BC}{2}
s= \frac{15.81+18.60+20.40}{2}
s= \frac{54.81}{2}
s=27.41

Finally, to find the area of our triangle, we are going to use Heron's formula:
A= \sqrt{s(s-AB)(s-AC)(s-BC)}
A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}
A= \sqrt{27.41(11.6)(8.81)(7.01)}
A=140.13

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0
3 years ago
9. Find the value of x. Round to the nearest degree.
Setler79 [48]
I need more information to answer this
3 0
3 years ago
Find the sum of deviation of all observations of the data 5, 8, 10, 15, 22 from their mean.​
ivann1987 [24]

Answer:

the sum of deviation of all observations of the data 5, 8, 10, 15, 22 from their mean. =26

Step-by-step explanation:

Mean=sum of observation/ No. of observation

={5+8+ 10+ 15 + 22}/5

=60/5=12

Sum of deviations

= |5- 12| + |8 – 12| + |10- 12| + |15- 12| + |22-12|

= 7+4+2+ 3+ 10

= 26

3 0
3 years ago
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