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KiRa [710]
3 years ago
6

I need help with 17-22

Mathematics
1 answer:
DIA [1.3K]3 years ago
5 0

Answer:

-5

Step-by-step explanation:

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Helppp pleasee!! If you can answer ASAP I would really appreciate it thank youuu.
Lady bird [3.3K]

Answer:

1. 4/7 = 16/28

Check:

(4/7)(4/4) = 16/28 = 16/28

2. 40/15 = 8/3

Check:

(40/15)/(5/5) = 8/3

3. 15/6 = 5/2

Check:

(15/6)/(3/3) = 5/2

4. 8/11 = 56/77

Check:

(8/11)(7/7) = 56/77

5. 9/2 = 63/14

Check:

(9/2)(7/7) = 63/14

~

7 0
3 years ago
Jerry's geometry teacher drew a triangle with angles that measured 120°, 34°, and 26°. What can Jerry classify the triangle as?
fgiga [73]

Answer:

b.obtuse

Step-by-step explanation:

if it is obtuse it has 1 angle over 90° and two angles under 90°

8 0
3 years ago
Read 2 more answers
1. The US Mint has a specification that pennies have a mean weight of 2.5g. From a sample of 37 pennies, the mean weight is foun
Evgesh-ka [11]

Answer:

the pennies does not conform to the US mints specification

Step-by-step explanation:

z = (variate -mean)/ standard deviation

z= 2.5 - 2.4991 / 0.01648 = 0.0546

we are going to check the value of z in the normal distribution table, which is the table bounded by z.

checking for z= 0.0 under 55 gives 0.0219 (value gotten from the table of normal distribution)

we subtract the value of z from 0.5 (1- (0.5+0.0219)) = 0.4781 > 0.05claim

since 0.4781 > 0.05claim, therefore, the pennies does not conform to the US mints specification

the claim state a 5% significance level whereas the calculated significance level is 47.81%. therefore, the claim should be rejected

7 0
3 years ago
5(3x + 9) -2x = 15x-2(x-5)
ipn [44]

Answer:

15x+45-2x=15x-2x-10

13x+45=13x+10

13x-13x=10-45

if you simplify further

you will not get an answer there is a mistake in the question

3 0
2 years ago
1. Write an equation in slope-intercept form for a line passing through (-3,3) with a slope of 1.
PIT_PIT [208]

1)


\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{3})~\hspace{10em} slope = m\implies 1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-3=1[x-(-3)] \\\\\\ y-3=1(x+3)\implies y-3=x+3\implies y=x+6


2)


\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{12}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{12-2}{1-(-4)}\implies \cfrac{10}{1+4}\implies \cfrac{10}{5}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=2[x-(-4)]\implies y-2=2(x+4) \\\\\\ y-2=2x+8\implies y=2x+10

8 0
3 years ago
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