Step-by-step explanation:
there are 7 decimal places from between 2 and 3 to the very end. so the answer is 7
The second equation, its setup is correct
The range is all positive values...
R{y | y>0}
Range > "Y" such that y is greater than 0
There is 15 bars in each case.
Subtract 8 from 143 and you get 135.
Divide 135 by 9 and you get 15 :)
The answer to this one is the 3rd one
