Answer:
I can help you just post another thing because there is no picture.
Step-by-step explanation:
Answer:
(C) 10 units
Step-by-step explanation:
It is given that EFGH is a rhombus and EG = 16 and FH = 12.
We know that the diagonals of the rhombus are the perpendicular bisectors, therefore OF=6, OH=6, OE=8 and OG=8.
Now, using the Pythagoras theorem in ΔOFG, we have
Thus, the value of the side of the rhombus will be 10 units.
Hence, option C is correct.
Answer:
The answer is 156 Hope it helps!
Step-by-step explanation:
Supplementary angles , when added, = 180
complimentary angles, when added, = 90
< AQC + < GQC = 180.....supplementary
< BQD + < DQE = 90.......complimentary
< CQE + < EQF = 90.......complimentary
< GQF , < FQE.....neither
< BQC + < DQC = 90....complimentary
< W and < X are supplementary...
if < W = 37, then < X = (180 - 37) = 143
< S and < T are complimentary
if < S = 64, then < T = (90 - 64) = 26
< C and < D are supplementary
if < C = 83, the < D = (180 - 83) = 97
cant read all of the last one.....but if they are complimentary, and
< U = 41, then the other angle is : (90 - 41) = 49
Answer:
X= -3
Y= 7
a= -6
b = -28
C = 9
D= -7
Step-by-step explanation:
2x – 4y = -34
-3x - y = 2
2x – 4y = -34
-12x - 4y = 8
-14x = 42
X= 42/-14
X= -3
-3x - y = 2
-3(-3) -y = 2
9-y = 2
9-2= y
Y= 7
a = 2x
a= 2*-3
a= -6
b = -4y
b = -4*7
b = -28
C= -3x
C= -3*-3
C = 9
D= -y
D= -7
