The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.
Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get
{P}_{n} =284\cdot {1.04}^{n}P
n
=284⋅1.04
n
We can find the number of years since 2013 by subtracting.
\displaystyle 2020 - 2013=72020−2013=7
We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.
\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P
7
=284⋅1.04
7
≈374
The student population will be about 374 in 2020.
Answer:
b
Step-by-step explanation:
i solved it in my head.
To get the number of years it will take for the tuition fee to double we use the compound interest formula, this is given by:
FV=p(1+r/100)^n
where:
FV=future value
p=principle
r=rate
n=years
from the information given, we are required to solve for n given that:
FV=$20,000
p=$10,000
r=7%
thus plugging in the formula we shall have:
20000=10000(1+7/100)^n
solving for n we have:
2=(1.07)^n
introducing natural logs we get:
n=ln2/ln1.07
n=10.25 years
Answer: 10.25 years
Adding up all of the values in the histogram, there were 20 cars sold in total. Of those, 5 were under 20 years old and 3 were more over 40. That means that 8/20 of the cars fit the bill. Multiplying the numerator and denominator by 5, we find that 8/20 = 40/100, or 40%.
I THINK it may be the fourth one.
