If the half-life is t, then every t days, the amount of the radioactive isotope will be cut in half.
(1/2)^(number of half-lives) = 3%
number of half-lives = ln(0.03) / ln(0.5)
This gives the number of half-lives as 5.06.
Then 300 days = (5.06)(length of 1 half-life)
length of 1 half-life = 300 / 5.06 = 59.29 days
Answer:
C) As x approaches positive infinity, f(x) approaches positive infinity
Step-by-step explanation:
- The domain is NOT all real numbers as x is either smaller than or bigger than 0, and smaller than or bigger than 2. So x ≠ 0 and x ≠ 2.
- This implies that there are asymptotes at x=0 and x=2.
Therefore, the function is NOT continuous.
- The function is NOT increasing over its entire domain as
f(x) = -x² -4x + 1 is decreasing for its given domain of 0<x<2
Answer:
1. √32
2. 4
3. 5
4. √29
5. √10
6. 5√2
Step-by-step explanation:
Use Pythagoras
Answer:
the second one
Step-by-step explanation:
Answer:
210
Step-by-step explanation:
JQ is 5 times the length of JK
● JQ = 5JK
JK = 42
● JQ = 5 × 42
● JQ = 210
