Polygon Diagonals. The number of diagonals in a polygon = n(n-3)/2, where n is the number of polygon sides. For a convex n-sided polygon, there are n vertices, and from each vertex you can draw n-3 diagonals, so the total number of diagonals that can be drawn is n(n-3).
This doesn’t make any sense
Answer:

Step-by-step explanation:
Answer:
a=
Step-by-step explanation:
vf=vi + at
vf-vi= at
divide both sides by t
=
a=
1. false because it has only 2 triangular faces
2. true
3. true
4. i think its false, it has four
5.