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Ann [662]
3 years ago
14

Expression that equals 118

Mathematics
1 answer:
Andrei [34K]3 years ago
5 0
Here are the following multiples:
59 * 2 = 118

and 118 * 1 = 118

The * means times.
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I need help plz Will give brainlyist (no links)
leva [86]

Answer:

20m^2

5 x 8 = 40/2 = 20m^2 or 20m squared

I hope this helps

3 0
3 years ago
4x-32=-8 what is the variable x
luda_lava [24]

Hey!

-------------------------------------------------

Steps To Solve:

4x - 32 = -8

~Add 32 to both sides

4x - 32 + 32 = -8 + 32

~Simplify

4x = 24

~Divide 4 to both sides

4x/4 = 24/4

~Simplify

x = 6

-------------------------------------------------

Answer:

x = 6

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Hope This Helped! Good Luck!

8 0
4 years ago
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A cube has a volume of 216 cubic centimeters. What can be concluded about this cube? Check all that apply. Recall the formula Cu
Elena L [17]

Second option: This is a perfect cube.

Fourth option: The side length is 6 centimeters.

Fifth option: Taking the cube root of the volume will determine the side length.

Step-by-step explanation:

You know that the volume of a cube can be calculated with:

Where s is the lenght of any side of the cube.

Since you know the volume of this cube, you can calculate the side lenght by  solving for "s". You can make this taking the cube root of the volume.

Therefore, you get that the side lenght of this cube is:

 

(Since it has exact cube root, it is a perfect cube)

4 0
3 years ago
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Solve using substitution please<br><br> y=-3x - 10<br> y = 6x + 8
Kamila [148]
6x+8=-3x-10
9x=-18
x=-2
-3(-2)-10=-4
So x=-2 and y=-4
5 0
4 years ago
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A computer can be classified as either cutting dash edge or ancient. Suppose that 86​% of computers are classified as ancient. ​
andrezito [222]

Answer:

(a) The probability that both computers are ancient is 0.7396

(b) The probability that all seven computers are ancient is 0.3479

(c) The probability that at least one of seven randomly selected computers is cutting dash edge is 0.6520.

Because the probability is about 65% is it not unusual that at least one of seven randomly selected computers is cutting dash edge, it's more likely than not.

Step-by-step explanation:

We know that 86​% of computers are classified as ancient. This means, if one computer is chosen at random, there is an 86% chance that it will be classified as ancient.

P(ancient)=0.86

(a) To find the probability that two computers are chosen at random and both are ancient​ you must,

The probability that the first computer is ancient is P(ancient)=0.86 and the probability that the second computer is ancient is P(ancient)=0.86

These events are independent; the selection of one computer does not affect the selection of another computer.

When calculating the probability that multiple independent events will all occur, the probabilities are multiplied, this is known as the rule of product.

Let A be the event "the first computer is ancient" and B the event "the second computer is ancient".

P(A\:and \:B)=P(A)\cdot P(B)=0.86\cdot 0.86=0.86^2= 0.7396

(b) To find the probability that seven computers are chosen at random and all are ancient​ you must,

Following the same logic in part (a) we have

Let A be the event "the first computer is ancient",

B the event "the second computer is ancient",

C the event "the third computer is ancient",

D the event "the fourth computer is ancient",

E the event "the fifth computer is ancient",

F the event "the sixth computer is ancient", and

G the event "the seventh computer is ancient"

P(A\:and \:B\:and \:C\:and \:D\:and \:E\:and \:F\:and \:G)=\\P(A)\cdot P(B)\cdot P(C)\cdot P(D)\cdot P(E)\cdot P(F)\cdot P(G) =(0.86)^7=0.3479

(c) To find the probability that at least one of seven randomly selected computers is cutting dash edge​ you must

Use the concept of complement. The complement of an event is the subset of outcomes in the sample space that are not in the event.

Let C the event "the computer is cutting dash edge".

Let A the event "the seven computers are ancient".

P(C)=1-P(A)=1-0.3479=0.6520

Because the probability is about 65% is it not unusual that at least one of seven randomly selected computers is cutting dash edge, it's more likely than not.

5 0
3 years ago
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