Answer:
y = 33.75 m/s.
Step-by-step explanation:
The graph of the rocket's velocity with respect to time looks as follows :
...(1)
Where x is time in seconds
We need to find the velocity of rocket after 15 seconds. Put x = 15 in equation (1).
![y=0.15\times (15)^2\\\\=33.75\ m/s](https://tex.z-dn.net/?f=y%3D0.15%5Ctimes%20%2815%29%5E2%5C%5C%5C%5C%3D33.75%5C%20m%2Fs)
Hence, the speed of the rocket after 15 seconds is 33.75 m/s.
Angle E = 180 -45 -63 = 72 degrees
Using the Law of Sines
FD / sine (E) = ED / sine (63)
3.8 / 0.95106 = ED / 0.89101
side DE = 3.8 * .89101 / .95106
side DE =
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3.5600677139
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Source:
http://www.1728.org/trigtut2.htm
Answer is 14 hope this helps
2(w+6)
2•w = 2w
2•6 = 12
2w+12 ? I hope this helped ♀️
Answer:
the 2nd one
Step-by-step explanation: