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zhannawk [14.2K]
3 years ago
6

What is the value of x?

Mathematics
1 answer:
lawyer [7]3 years ago
8 0

Answer:

B.) 45 degrees

Step-by-step explanation:

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What is the area of the polygon below?<br> 5<br> 17<br> 11<br> 10
svetoff [14.1K]
I thinks it 5 umm ...forgive me if I’m wrong
3 0
3 years ago
Convert,the complex number into polar form: 4+4i
kow [346]
Z = a + bi
z = 4 + 4i

r² = a² + b²
r² = (4)² + (4)²
r² = 16 + 16
r² = 32
 r = 4√(2)
 r = 4(1.414)
 r = 5.656

cos\theta = \frac{a}{r}
cos\theta = \frac{4}{4\sqrt{2}}
cos\theta = \frac{4}{4\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}}
cos\theta = \frac{4\sqrt{2}}{4\sqrt{4}}
cos\theta = \frac{4\sqrt{2}}{4(2)}
cos\theta = \frac{4\sqrt{2}}{8}
cos\theta = \frac{\sqrt{2}}{2}
2(cos\theta) = 2(\frac{\sqrt{2}}{2})
2cos\theta = \sqrt{2}
2cos\theta = 1.414

sin\theta = \frac{b}{r}
sin\theta = \frac{4}{4\sqrt{2}}
sin\theta = \frac{4}{4\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}}
sin\theta = \frac{4\sqrt{2}}{4\sqrt{4}}
sin\theta = \frac{4\sqrt{2}}{4(2)}
sin\theta = \frac{4\sqrt{2}}{8}
sin\theta = \frac{\sqrt{2}}{2}
2(sin\theta) = 2(\frac{\sqrt{2}}{2})
2sin\theta = \sqrt{2}
2sin\theta = 1.414

z = a + bi
z = rcosθ + (rsinθ)i
z = r(cosθ + i sinθ)

z = 4 + 4i
z = 5.656cosθ + (5.656sinθ)i
z = 5.656(cosθ + i sinθ)
z = 5.656(cos45 + i sin45)

\theta = tan^{-1}\frac{b}{a}
\theta = tan^{-1}\frac{4}{4}
\theta = tan^{-1}(1)
\theta = 45

The polar form of 4 + 4i is approximately equal to 5.656(cos45 + i sin45).
5 0
3 years ago
Find the value of x which ABCD must be a parallellogram?<br> x =
Serggg [28]
If\ ABCD\ is\ parallelogram,\ then:\\\\25x+1=7x+37\ \ \ |subtract\ 1\ from\ both\ sides\\\\25x=7x+36\ \ \ \ |subtract\ 7x\ from\ both\ sides\\\\18x=36\ \ \ \ |divide\ both\ sides\ by\ 18\\\\\boxed{x=2}
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3 years ago
3x-9=-21 equation in words
sergeinik [125]
'nine less than three times a number is negative twenty-one.'
5 0
3 years ago
Pleeeeeeeeese help quik
Ilya [14]

Answer:

#3

Step-by-step explanation:

8 0
3 years ago
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