The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
<h3>What is the least number of buses needed to carry 710 passengers? </h3>
Given that;
- Number of passengers n = 710
- Least number of buses need B = ?
To get the least number of buses, we say;
Number of buses B = 710 ÷ 150
Number of buses B = 4.7 ≈ 5
The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
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Answer:
P=7
Step-by-step explanation:
Answer: The first table represents a function!
Step-by-step explanation:
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Answer:
25.5 and 37.5
Step-by-step explanation:
x+y=63
x-y = 12 then x = 12 + y sub this into the first equation
(12+y) + y = 63
12 + 2y = 63
2y = 51
y = 25.5 then x = 37.5
Answer:
a
12=
−
3
n
2
−
n
Step-by-step explanation: