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4 years ago

Does water in a glass have mass

Chemistry

2 answers:

igor_vitrenko [27]4 years ago

6 0

Answer:

A glass of water, or 200 grams of water, therefore contains 6.6855 × 1024 water molecules. The total mass of the hydrosphere is about 1.4 × 1024 grams, and thus the total hydrosphere contains about 7 × 1021 glasses of water (with 200 grams of water in each).

Explanation:

Olenka [21]4 years ago

5 0

Answer:

Just like solids, liquids also have their own characteristic density. ... Just like a solid, the density of a liquid equals the mass of the liquid divided by its volume; D = m/v. The density of water is 1 gram per cubic centimeter. The density of a substance is the same regardless of the size of the sample.

Matter is generally defined as any thing that has mass and occupies spaces. Matter is generally divided into three categories ; solid, liquid and gas. Water is a liquid, water has does have molecules, thus has a mass, and is suspended in an area such as water in glass.

<h2><u><em>SO YES WATER IN A GLASS HAS MASS :)</em></u></h2>

Hope this helps ~OwO~

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What would happen to the block if it had a density of 0.500 kg/L and was placed in the same 100.0 L tank of water?

raketka [301]

I’m not sure if there was important information in the question before this one, but the answer based on the info I have is B.

The density of water is 1kg/L. Since the density of the block is less, it will float.

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4 years ago

Read 2 more answers

Propanoic acid, ch3ch2cooh, has a pka =4.9. draw the structure of the conjugate base of propanoic acid and give the ph above whi

xenn [34]

Conjugate base of Propanoic acid ( $CH_{3}CH_{2}COOH$ is propanoate where -COOH group gets converted to -CO $O^{1-}$ . The structure of conjugate base of Propanoic acid is shown in the diagram.

The $p^{H}$ above which 90% of the compound will be in this conjugate base form can be determined using Henderson's equation as propanoic acid is weak acid and it can form buffer solution on reaction with strong base.

$p^{H}$ = $p^{k_{a}$ + log $\frac{[Conjugate base]}{[acid]}$ =4.9+log $\frac{90}{10}$ =5.85

As 90% conjugate base is present, so propanoic acid present 10%.

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4 years ago

The C=C bond in 2-cyclohexenone produces an unusually strong signal. Explain using resonance structuresBased on the above resona

frosja888 [35]

Answer:

When two single single bonds separated by a double bond (e.g C=C-C=C or C=C-C=O in the case of 2-cyclohexenone), the effect of resonance among those there bonds will be observed.

Explanation:

Since the Oxygen atom has higher electronegativity, it will cause the electrons in the resonance bonds 'flow' toward the Oxygen atom, so that the C=C will 'lose' some electron. The signal read for that bond will be different from other alkene structure.

Attachment is the resonance structure of 2-cyclohexene.

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3 years ago

What do you put in the calculator to get the molar mass of Mg3P2

olga55 [171]

Input the atomic masses of Mg and P to give 134.84g/mol

Explanation:

The molar mass of a substance (atom or molecule or compound) is the mass in grams of one mole of the substance:

When dealing with an element the molar mass is the relative atomic mass expressed as g/mol.

For compounds, you add the atomic masses of the component atoms and you sum up.

You simply input the atomic mass of 3 atoms of Mg and 2 atoms of P

Atomic mass of Mg = 24.3g/mol

P = 30.97g/mole

Molar mass of Mg₃P₂ = 3(24.3) + 2(30.97) = 134.84g/mol

learn more:

Molar mass brainly.com/question/2861244

#learnwithbrainly

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3 years ago

The rate constant for the reaction 3A equals 4b is 6.00×10 how long will it take the concentration of a to drop from 0.75 to 0.2

Lelu [443]

This question is incomplete, the complete question is;

The rate constant for the reaction 3A equals 4B is 6.00 × 10⁻³ L.mol⁻¹min⁻¹.

how long will it take the concentration of A to drop from 0.75 to 0.25M ?

from the unit of the rate constant we know it is a second reaction order

OPTIONS

a) 2.2×10^−3 min

b) 5.5×10^−3 min

c) 180 min

d) 440 min

e) 5.0×10^2 min

Answer:

it will take 440 min for the concentration of A to drop from 0.75 to 0.25M

Option d) 440 min is the correct answer

Explanation:

Given that;

Rate constant K = 6.00 × 10⁻³ L.mol⁻¹min⁻¹

3A → 4B

given that it is a second reaction order;

k = 1/t [ 1/A - 1/A₀]

kt = [ 1/A - 1/A₀]

t = [ 1/A - 1/A₀] / k

K is the rate constant(6.00 × 10⁻³)

A₀ is initial concentration( 0.75 )

A is final concentration(0.25)

t is time required = ?

so we substitute our values into the equation

t = [ (1/0.25) - (1/0.75)] / (6.00 × 10⁻³)

t = 2.6666 / (6.00 × 10⁻³)

t = 444.34 ≈ 440 min {significant figures}

Therefore it will take 440 min for the concentration of A to drop from 0.75 to 0.25M

Option d) 440 min is the correct answer

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3 years ago