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3 years ago

5

The following phase diagram shows how a catalyst affected the rate of a reaction.

2 answers:

Maslowich3 years ago

8 0

The correct answer is C

Oduvanchick [21]3 years ago

5 0

Answer:

The correct answer is "The catalyst decreased the activation energy of the reactants."

Explanation:

Activation energy is the minimum energy required to start a reaction. A catalyst lowers the activation energy of a reaction. Here the catalyst lowers the activation energy of the reactant, thus making it easier to start to the reaction. In the absence of a catalyst the activation energy of the reactant will be higher.

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Compute 9.3456+2140.56. Round the answer appropriately.

vichka [17]

This is just addition. Put 2140.56 on top, line up 9.3456 under it appropriately. Doing this will give you the answer: 2149.9056

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3 years ago

Please help also some of them may be multiple choice, thank you.

Maurinko [17]

Answer: what are the answers to the questions

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3 years ago

Excited lithium ions emit radiation at a wavelength of 670.8 nm in the visible range spectrum. Calculate the frequency of a phot

zzz [600]

Answer : The frequency of a photon of radiation is, $4.47\times 10^9s^{-1}$

Explanation : Given,

Wavelength of the radiation = 670.8 nm

First we have to convert wavelength form 'nm' to 'm'.

Conversion used : $(1nm=10^{-9}m)$

So, the wavelength of the radiation = 670.8 nm = $670.8\times 10^{-9}m$

Now we have to calculate the frequency of a photon of radiation.

Formula used : $\nu =\frac{c}{\lambda}$

where,

$\nu$ = frequency of a photon of radiation

$\lambda$ = wavelength of the radiation

c = speed of light = $3\times 10^8m/s$

Now put all the given values in the above formula, we get the frequency of a photon of radiation.

$\nu =\frac{3\times 10^8m/s}{670.8\times 10^{-9}m}$

$\nu =4.47\times 10^9s^{-1}$

Therefore, the frequency of a photon of radiation is, $4.47\times 10^9s^{-1}$

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4 years ago

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Lisa [10]

MITOCHONDRIA.
The powerhouse of a cell is Mitochondria, don’t you even forget this.

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