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Andreas93 [3]
3 years ago
5

The following phase diagram shows how a catalyst affected the rate of a reaction.

Chemistry
2 answers:
Maslowich3 years ago
8 0
The correct  answer is C
Oduvanchick [21]3 years ago
5 0

Answer:

The correct answer is "The catalyst decreased the activation energy of the reactants."

Explanation:

Activation energy is the minimum energy required to start a reaction. A catalyst lowers the activation energy of a reaction. Here the catalyst lowers the activation energy of the reactant, thus making it easier to start to the reaction. In the absence of a catalyst the activation energy of the reactant will be higher.

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How do you find the mole ratio of a compound?
tangare [24]
Simply divide the moles of a reactant by the number of moles of product
8 0
3 years ago
how power station that produce electricity affect our environment what can we do to minimize these harmful effects?​
allsm [11]

Answer:

they help becuz they dont use any extra power and the are reneable

6 0
2 years ago
217 mL of neon gas at 551 celsius is brought to standard temperature (0 celsius) while the pressure is held constant. What is th
pantera1 [17]

Answer: The new volume is 72 ml

Explanation:

To calculate the final volume of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=217ml\\T_1=551^oC=(551+273)K=824K\\V_2=?\\T_2=0^0C=(0+273)K=273K

Putting values in above equation, we get:

\frac{217ml}{824K}=\frac{V_2}{273K}\\\\V_2=72ml

Thus the new volume is 72 ml

7 0
2 years ago
2. A sample of neon gas has a volume of 87.6 L at STP. How many moles are present?
PSYCHO15rus [73]

Answer:

                      3.91 moles of Neon

Explanation:

According to Avogadro's Law, same volume of any gas at standard temperature (273.15 K or O °C) and pressure (1 atm) will occupy same volume. And one mole of any Ideal gas occupies 22.4 dm³ (1 dm³ = 1 L).

Data Given:

                 n = moles = <u>???</u>

                 V = Volume = 87.6 L

Solution:

               As 22.4 L volume is occupied by one mole of gas then the 16.8 L of this gas will contain....

                          = ( 1 mole × 87.6 L) ÷ 22.4 L

                          = 3.91 moles

<h3>2nd Method:</h3>

                     Assuming that the gas is acting ideally, hence, applying ideal gas equation.

                              P V  =  n R T      ∴  R  =  0.08205 L⋅atm⋅K⁻¹⋅mol⁻¹

Solving for n,

                              n  =  P V / R T

Putting values,

                              n  =  (1 atm × 87.6 L)/(0.08205 L⋅atm⋅K⁻¹⋅mol⁻¹ × 273.15K)

                              n  =  3.91 moles

Result:

          87.6 L of Neon gas will contain 3.91 moles at standard temperature and pressure.

7 0
3 years ago
HELP! URGENT Which of the following best states the relationship between erosion and deposition?
MariettaO [177]
The answer is A: When the energy transporting sediments diminishes, the sediments settle in a low-lying area; therefore, deposition always follows erosion
7 0
3 years ago
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