Question

6. Find the product for both sets of polynomials below by multiplying vertically.

Answer 1

Answer:

A) $4x^5-4x^4-16x^2+16x$

B) $4x^4-4x^3-16x^2+16x$

Also, maybe that vertically means:

A) $4x^2 \cdot x^3$    and $(-4x) \cdot (-4)$

Resulting in $4x^5+16x$

B) $x^2 \cdot 4x^2$    and  $x \cdot (-8x)$  and $-2 \cdot 0$

Resulting in $4x^4-8x^2$

Step-by-step explanation:

It seems that you want to multiply the polynomials in this way: $(\text{Polynomial - 1})\cdot(\text{Polynomial - 2})$

A)

$4x^2-4x$

$x \cdot x^2 -4$

$(4x^2-4x)(x \cdot x^2 -4)=(4x^2-4x)(x^3 -4)$

$(4x^2-4x)(x^3 -4)$

$4x^5-16x^2-4x^4+16x$

$4x^5-4x^4-16x^2+16x$

B)

$x^2+x-2$

$4x^2-8x$

$(x^2+x-2)(4x^2-8x)$

$4x^4-8x^3+4x^3-8x^2-8x^2+16x$

$4x^4-4x^3-16x^2+16x$