Ise is shown in this scale drawing. The height of the horse in the drawing is 4.5 inches

Find the area of the shaded regions. Give your answer as a completely simplified

Snezhnost [94]

Do the area of the circle as a whole minus (72/360 x radius^2) and then minus the other grey area.

8 0

3 years ago

Which proportion can you use to find the value of a?

Ugo [173]

<u>Given</u>:

The given triangle is a similar triangle.

The length of the hypotenuse is 18 units.

The length of the leg is a.

The length of the part of the hypotenuse is 16 units.

We need to determine the proportion used to find the value of a.

<u>Proportion to find the value of a:</u>

We shall find the proportion to determine the value of a using the geometric mean leg rule.

Applying the leg rule, we have;

$\frac{\text { hypotenuse }}{\text { leg }}=\frac{\text { leg }}{\text { part }}$

Substituting the values of hypotenuse, leg and part, we get;

$\frac{18}{a}=\frac{a}{16}$

Thus, the proportion used to find the value of a is $\frac{18}{a}=\frac{a}{16}$

Hence, Option D is the correct answer.

6 0

3 years ago

When Theresa got her puppy, it weighed 6 ponds less than 2/3 of its weight now. If the puppy weighed 4 pounds when she first rec

sesenic [268]

Answer:

15 lb

Step-by-step explanation:

let the current weight of the puppy be X, the initial weight of the puppy is 4lb or $\frac{2}{3}X-6\ lb$ , (6 lb less 2/3 X) .

#We equate the current weight to the initial weight to determine X:

$4\ lb=\frac{2}{3}X-6\ lb\\\\10 \ lb=\frac{2}{3}X\\\\X=15$

Hence, the current weight of the puppy is 15 lb

5 0

3 years ago

Determine the number of degrees of freedom for the two-sample t test or CI in each of the following situations. (Round your answ

gulaghasi [49]

Answer:

Part a ) The degrees of freedom for the given two sample non-pooled t test is 24

Part b ) The degrees of freedom for the given two sample non-pooled t test is 30

Part c ) The degrees of freedom for the given two sample non-pooled t test is 30

Part d ) The degrees of freedom for the given two sample non-pooled t test is 25

Step-by-step explanation:

Degrees of freedom for a non-pooled two sample t-test is given by;

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Now given the information;

a) :- m = 12, n = 15, s₁ = 4.0, s₂ = 6.0

we substitute

Δf = {[ 4²/12 + 6²/15 ]²} / {[( 4²/12)²/12-1] + [(6²/15)²/15-1]}

Δf = 30184 / 1241

Δf = 24.3223 ≈ 24 (down to the nearest whole number)

b) :- m = 12, n = 21, s₁ = 4.0, s₂ = 6.0

we substitute using same formula

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Δf = {[ 4²/12 + 6²/21 ]²} / {[( 4²/12)²/12-1] + [(6²/21)²/21-1]}

Δf = 56320 / 1871

Δf = 30.1015 ≈ 30 (down to the nearest whole number)

c) :- m = 12, n = 21, s₁ = 3.0, s₂ = 6.0

we substitute using same formula

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Δf = {[ 3²/12 + 6²/21 ]²} / {[( 3²/12)²/12-1] + [(6²/21)²/21-1]}

Δf = 29095 / 949

Δf = 30.6585 ≈ 30 (down to the nearest whole number)

d) :- m = 10, n = 24, s₁ = 4.0, s₂ = 6.0

we substitute using same formula

Δf = {[ s₁²/m + s₂²/n ]²} / {[( s₁²/m)²/m-1] + [(s₂²/n)²/n-1]}

Δf = {[ 4²/10 + 6²/24 ]²} / {[( 4²/10)²/10-1] + [(6²/24)²/24-1]}

Δf = 1044 / 41

Δf = 25.4634 ≈ 25 (down to the nearest whole number).

6 0

3 years ago

At Jim's Juice Box Factory, his machine can fill 300 juice boxed an hour. Each juice box holds 0.8 cups. How many gallons of jui

12345 [234]

(300 box/h) * (0.8 cup/box) * (1 gal)/(16 cup) = 300*0.8/16 gal/h
.. = 15 gal/h

Jim's factory needs 15 gallons of juice per hour.

8 0

3 years ago