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Elza [17]
3 years ago
5

A student wants to prove that the base angles of an isosceles triangle are congruent. The student draws isosceles triangle ABC w

ith base angles B and C.
Point M is drawn as the midpoint of BC.

Which of the following could be used as part of the proof that B = C? Select all that apply

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
6 0

Answer:

BM=CM bc of the definition of midpoint

AB =AC bc of the def of an isosceles triangle

and angle B = angle D becasur corresponding parts

Step-by-step explanation:

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PLEASE HELP THANK YOU
arsen [322]

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Similarities.

Since here, first figure is a Triangle, hence similarity of a triangle is given by ratio of it sides and make them equate,

hence for,

1.) 16/12 = x/9 ===> 4/3 = x/9 ===> x = 9*4/3 ==> x = 36/3

hence the value of x is 12 , ===> x = 12 .

2.) here,in the case of a Reactangle the relation is such that, length = 2* breadth,

hence we apply the relation,

x = 2*4.5 ===> x = 9 units.

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3 years ago
Rachel types 162 words in 3 minutes. Rachel types at a constant rate.
Mazyrski [523]

Answer:

rise

Step-by-step explanation:

8 0
3 years ago
Determine the point on the graph of the linear equation 2x + 5y = 19, whose ordinate is 1 1/2 times its abscissa.
rosijanka [135]

Answer:

(2, 3)

Step-by-step explanation:

2x + 5y = 19

5y = -2x + 19

y = -\frac{2}{5} x + \frac{19}{5}

P(abscissa, ordinate)

P(x, 1.5x)

P(2, 3)

3 = -\frac{2}{5} (2) + \frac{19}{5}

3 = -\frac{4}{5} + \frac{19}{5}

3 = 15/5

3 = 3

8 0
4 years ago
Given that the chord ef is a diameter of circle d which of the following names major arc
zubka84 [21]
1) Diameter = Line MN, Chord = Line LN 
<span>2) B --- GFC </span>
<span>3) C --- GCE </span>
4 0
3 years ago
Jason had $32. He spent all the money on buying 4 CDs for $x each and 2 magazines for $y each. If Jason had bought 5 CDs and 2 m
Leni [432]
You can set up two equations from the information given. I will set them up for you:

32 = 4x + 2y
36 = 5x + 2y

Let's solve the first equation to come up with a value for y.

32 = 4x + 2y
32 - 4x = 2y
16 - 2x = y

Now we plug y into the other equation.

36 = 5x + 2(16-2x)
36 = 5x + 32 - 4x
4 = x

Now we have our real x value and we can plug it into the first equation.

32 = 4(4) + 2y
32 = 16 + 2y
16 = 2y
8 = y

Since x = 4 and y = 8, you get the final coordinates of (4,8).

Your answer is the second statement provided above.
3 0
3 years ago
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