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olga55 [171]
3 years ago
5

Find area and round to nearest thousandth

Mathematics
1 answer:
vesna_86 [32]3 years ago
3 0

Answer:

236.715 ft²

Step-by-step explanation:

The figure consists of the rectangle with sides 15 ft and 4 ft and two semicircles with diameter 15 ft (radius 7.5 ft).

The area of the rectangle is

A₁=15·4=60 ft²

The area of two semicircles together is the area of circle. Thus,

A₂=πr²=π·7.5²=56.25π≈176.715 ft²

The area of the figure is

A=A₁+A₂=60+176.715=236.715 ft²

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nordsb [41]

Answer:

<em>A growth present such that the change in slope itself differs by the multiplication of a constant</em>

Step-by-step explanation:

<em>* Definition: </em><em>A growth present such that the change in slope itself differs by the multiplication of a constant </em><em>*</em>

8 0
3 years ago
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Plz show work <br> 3(10-x)=21
Contact [7]

Answer:

x = 3

Step-by-step explanation:

3(10-x)=21

30-3x=21

-30      -30

-3x=-9

x=3

5 0
3 years ago
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Find the length of JL<br> 15<br> None of the other answers are correct<br> 12<br> 3
r-ruslan [8.4K]

Answer:

D: 12

Step-by-step explanation:

The entire segment KI is composed of the segments KJ and JI. So:

KI=KJ+JI

We know that KI is 15.

KJ is (2x-15) and JI is (2x-6). Substitute:

15=(2x-15)+(2x-6)

Solve for x. Combine like terms:

15=4x-21

Add 21 to both sides:

4x=36

Hence, the value of x is:

x=9

We know that JI is 2x-6.

We will substitute 9 for x to find JI. So:

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Hence, our answer is D.

3 0
3 years ago
A decorative steel frame is shown below it is made of a circular section and and 6 stems the length of each stem is 45 cm work o
lutik1710 [3]

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552.78

Step-by-step explanation:

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3 years ago
PLEASE HELP 45 POINTS!!!!!
Nady [450]

Answer:

  • \sf x = 5
  • \sf DF = 12

setting up proportionality equation:

\sf \dfrac{big-side}{big-diagonal}   = \sf \dfrac{small-side}{small-diagonal}

\sf \hookrightarrow \dfrac{7}{16+x+7}  = \dfrac{4}{16}

\sf \hookrightarrow  \dfrac{7}{23+x}  = \dfrac{4}{16}

\sf \hookrightarrow 4(23+x) = 112

\sf \hookrightarrow 92 + 4x = 112

\sf \hookrightarrow 4x = 112- 92

\sf \hookrightarrow 4x = 20

\sf \hookrightarrow x = 5

<u>Find DF:</u>

\hookrightarrow \sf x + 7

\hookrightarrow \sf  5 + 7

\hookrightarrow \sf 12

4 0
2 years ago
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