Carl sells $450 worth of merchandise. How much money will Carl get to keep if he receives 30% commission?

Help please!!!!! ASAP!!! Only brainliest answer gets points. No wrong answers. Only answer if you know how to do this.

FinnZ [79.3K]

Answer:

The number of pounds of coffee in stock decreased by 9% each hour since the trend began.

There were 40 pounds of coffee in stock when the trend began.

Step-by-step explanation:

p(x)=0.4(.91)^x

= a b^x

where a is the initial value and b = 1-rate of decrease

We know that the number of pounds of coffee will decrease as time goes on.

.4 is the initial value

It is in the hundreds of pound

.4 * 100 = 40 pounds

x is the number of hours

.91 = 1- rate of decrease

Subtract 1 from each side

.91-1 =-rate of decrease

-.09 = -rate of decrease

rate of decrease = .09

rate of decrease = 9 %

That means we keep 91 % of the coffee and sell 9% of the coffee

Lets check the statements:

There were 400 pounds of coffee in stock when the trend began.

False there were 40 pounds when we started

The number of pounds of coffee in stock decreased by 9% each hour since the trend began.

True see above calculations

There were 4000 pounds of coffee in stock when the trend began.

False see above calculations

There were 40 pounds of coffee in stock when the trend began.

True see above calculations

The number of pounds of coffee in stock decreased by 91% each hour since the trend began.

False see above calculations

4 0

3 years ago

Which search method employs the use of markers such as knots at regular intervals along the search line to indicate distance fro

vovangra [49]

The wide-area search method employs the use of markers such as knots at regular intervals along the search line.

Given the method employs the use of markers such as knots at regular intervals along the search line to indicate distance from the beginning of the search line.

In order to locate, relieve distress, and preserve the life of a person who has been reported missing or is believed to be lost, stranded, or is considered a high-risk missing person, wide area search and rescue refers to activities occurring within large geographic areas. It also refers to the removal of any survivors to a safe location.

Hence, the wide-area search method employs the use of markers such as knots at regular intervals along the search line to indicate distance from the beginning of the search line

Learn more about wide area from here brainly.com/question/15506214

#SPJ4

5 0

2 years ago

67. The line contains the point (4,0) and is parallel to the line defined by 3x = 2y.

olganol [36]

Answer:

$y=\frac{3}{2} x-6$

Step-by-step explanation:

Hi there!

What we need to know:

Linear equations are typically organized in slope-intercept form:

$y=mx+b$ where m is the slope of the line and b is the y-intercept (the value of y when the line crosses the y-axis)

Parallel lines will always have the same slope but different y-intercepts.

1) Determine the slope of the parallel line

Organize 3x = 2y into slope-intercept form. Why? So we can easily identify the slope, m.

$3x = 2y$

Switch the sides

$2y=3x$

Divide both sides by 2 to isolate y

$\frac{2y}{2} = \frac{3}{2} x\\y=\frac{3}{2} x$

Now that this equation is in slope-intercept form, we can easily identify that $\frac{3}{2}$ is in the place of m. Therefore, because parallel lines have the same slope, the parallel line we're solving for now will also have the slope $\frac{3}{2}$ . Plug this into $y=mx+b$ :

$y=\frac{3}{2} x+b$

2) Determine the y-intercept

$y=\frac{3}{2} x+b$

Plug in the given point, (4,0)

$0=\frac{3}{2} (4)+b\\0=6+b$

Subtract both sides by 6

$0-6=6+b-6\\-6=b$

Therefore, -6 is the y-intercept of the line. Plug this into $y=\frac{3}{2} x+b$ as b:

$y=\frac{3}{2} x-6$

I hope this helps!

7 0

3 years ago

Solve the following problems. I REALLY NEED HELP 80 POINTS!

lisabon 2012 [21]

Answer:

a 10 yd 2ft 7 in

b 10 yd 1 ft 2 in

c 99 yd

d. 4840 sq yd 7 sq ft 119 sq in

Step-by-step explanation:

a. 2 ft. 5 in. +

9 yd. 3 ft. 2 in.

---------------------

9 yd 5ft 7 in

but 3 ft = 1yd

9 yd 5ft 7 in

+1yd - 3ft

---------------------------

10 yd 2ft 7 in

b. 4 yd. 8 in

+ 6 yd. 6 in.

----------------------

10 yd 14 in

but 12 in = 1ft

10 yd 14 in

+ 1ft - 12 in

---------------------

10 yd 1 ft 2 in

c. 29 yd. 2 ft. 11 in.

55 yd. 1 ft. 10 in.

+ 13 yd. 1 ft. 3 in.

--------------------------

97 yd 4 ft 24 in

12 in = 1ft

24 in = 2ft

97 yd 4 ft 24 in

+2ft - 24 in

--------------------------------

97 yd 6ft

3 ft = 1yd

6f = 2yd

97 yd 6ft

+2yd - 6ft

---------------------

99 yd

d. 4,839 sq. yd. 8 sq. ft. 139 sq. in.

+ 7 sq. ft. 124 sq. in.

--------------------------------------------------

4839 sq yd 15 sq ft 263 sq in

12*12 = 144 sq in = 1 sq ft

4839 sq yd 15 sq ft 263 sq in

+ 1 sq ft - 144 sq in

--------------------------------------------------

4839 sq yd 16 sq ft 119 sq in

3ft * 3 ft = 9 sq ft = 1 sq yd

4839 sq yd 16 sq ft 119 sq in

+1 sq yd - 9 sq ft

----------------------------------------------

4840 sq yd 7 sq ft 119 sq in

8 0

3 years ago

Read 2 more answers

Can someone please help me with this!!

Aloiza [94]

Answer:

$407 yd^{2}$

Step-by-step explanation:

first find the area of the rectangle, which would be $16*13 = 208$ yd²

then find the arc length of the sector, which is about 30.6yd

use the arc length to find the area of the sector, which is about 199.09yd²

add together the area of the rectangle and sector:

199.09 + 208 ≈ 407

8 0

3 years ago