Answer:

Step-by-step explanation:


Use the formula of a³ - b³ = ( a - b) ( a² + ab + b² )


Hope I helped!
Best regards! :D
38
430
49
mph I think... maybe
C I’m not really sure but try
Answer:
4.47
Step-by-step explanation:
a^2+b^2=c^2
2^2+4^2=c^2
4+16=c^2
20=C^2
= 
4.47=c
100. When rounding to the hundreds place, you must consider the value of the digit in the tens place. If the digit in the tens place is 5 or greater, the digit in the hundreds place increases by 1. If the digit in the tens place is 4 or less the digit in the hundreds place remains the same. In this case, the number in the hundreds place was originally zero.