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3 years ago

Chad drove 168 miles in 3 hours How many miles per hour did Chad drive?

Mathematics

1 answer:

Masja [62]3 years ago

4 0

He drove 56 miles because if you divide 168 and 3 it equals 56.

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On a linear X temperature scale, water freezes at −115.0°X and boils at 325.0°X. On a linear Y temperature scale, water freezes

belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

$r = \frac{\Delta T_{X}}{\Delta T_{Y}}$

$r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}$

$r = 11\,\frac{^{\circ}X}{^{\circ}Y}$

The difference between current temperature in Y linear scale with respect to freezing point is:

$\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)$

$\Delta T_{Y} = 115\,^{\circ}Y$

The change in X linear scale is:

$\Delta T_{X} = r\cdot \Delta T_{Y}$

$\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)$

$\Delta T_{X} = 1265\,^{\circ}X$

Lastly, the current temperature on the X scale is:

$T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X$

$T_{X} = 1150\,^{\circ}X$

The current temperature on the X scale is 1150 °X.

5 0

3 years ago

If ABC=PQR, then BC=?

olya-2409 [2.1K]

If ABC=PQR, then
BC=QR

4 0

3 years ago

Write an equation in standard form using integers Y= - x — 5

kykrilka [37]

Answer:

x + y = - 5

Step-by-step explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Given

y = - x - 5 ( add x to both sides )

x + y = - 5 ← in standard form

8 0

3 years ago

When will the equation p(b)=520(0.88)^b have a value less than 100?

yulyashka [42]

Answer:

The given equation will have value less than 100 whenever the value of b is greater than 12.89

Step-by-step explanation:

For the given equation, p(b) = 520 × $0.88^{b}$ to have a value less than 100 we can establish inequality as:

p(b) < 100

or, 520 × $0.88^{b}$ < 100

or, $\frac{520}{520}$ × $0.88^{b}$ < $\frac{100}{520}$

or, $0.88^{b}$ < $\frac{1}{5.2}$

or, ㏒ ( $0.88^{b}$ ) < ㏒ ( $\frac{1}{5.2}$ )

or, b× ㏒ 0.88 < ㏒ ( $\frac{1}{5.2}$ )

or, $\frac{log (\frac{1}{5.2}) }{log (0.88)}$ < b

or, 12.89 < b

Hence for the equation to have value less than 100, b must be greater than 12.89.

3 0

3 years ago

How big is a piece of A4 paper?

svlad2 [7]

Answer:

210 x 297 mm

Hope that this helps!

5 0

3 years ago