P(x) = √x
for x = 0 → √0 = 0 and p(0) = 0
for x = 1.44 → √1.44 =1.2 and p(1.44) = 1.2
for x = 2.25 → √2.25 = 1.5 and p(2.25) = 1.5
for x = 3.24 → √3.24 = 1.8 and p(3.24) = 1.8
for x = 4.41 → √4.41= 2.1 and p(4.41) = 2.1
for x = 5.29 → √5.29 = 2.3 and p(5.29) = 2.3
Answer:
The solution of the given initial value problems in explicit form is
and the solutions are defined for all real numbers.
Step-by-step explanation:
The given differential equation is

It can be written as

Use variable separable method to solve this differential equation.

Integrate both the sides.

![[\because \int x^n=\frac{x^{n+1}}{n+1}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cint%20x%5En%3D%5Cfrac%7Bx%5E%7Bn%2B1%7D%7D%7Bn%2B1%7D%5D)
... (1)
It is given that y(1) = -2. Substitute x=1 and y=-2 to find the value of C.



The value of C is -2. Substitute C=-2 in equation (1).
Therefore the solution of the given initial value problems in explicit form is
.
The solution is quadratic function, so it is defined for all real values.
Therefore the solutions are defined for all real numbers.
Answer:
#UseSimplifiedExpression
Step-by-step explanation:
When a fraction corresponds to a repeating decimal, it's denominator is 9 or 99.
For example, 4/11 = 36/99 = 0.36 with bar notation over 36.
Example #2: 2/3 = 6/9 = 0.666....
or also written as 0.6 with bar notation over 6.
You know a fraction responds to a terminating decimal because it can be simplified to a terminating decimal.
Example: 2/4 = 0.5