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kodGreya [7K]
3 years ago
14

Kini and Duke are each working during the summer to earn money in addition to their weekly allowance, and they are saving all of

their money. Kini earns $9 an hour at her job, and her allowance is $8 per week. Duke earns $7.50 an hour, and his allowance is $17 per week. How many hours do Kini and Duke need to work in order to save the same amount of money in one week?
Mathematics
1 answer:
postnew [5]3 years ago
4 0

Answer:

6hrs

Step-by-step explanation:

First, we have to put the information given to us about the money they earn into an expression

let x represent the number of hours Kini and Duke work and y represent the total amount of money they earn in a week.

y(kini) = 9x + 8

y(duke) = 7.5x + 17

Now we subtract the x values and the constant values

9x - 7.5x = 1.5x

17 - 8 = 9

Make these into an equation

1.5x = 9

Divide both sides by 1.5 so x(the number of hours the both work) can stand alone.

\frac{1.5x}{1.5}= \frac{9}{1.5}

x = 6 hrs

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Part A)

A reasonable domain to plot the growth function is:

0\leq d \leq 12

Part B)

The <em>y-</em>intercept represents that when the biologist started her study, the radius of the algae was five millimeters.

Part C)

The average rate of change from <em>d</em> = 4 to <em>d</em> = 11 was about 0.11. This means that from the 4th day to the 11th, the radius of the algae grew, on average, at a rate of 0.11 mm per day.

Step-by-step explanation:

The radius of the algae f(d) in millimeters after <em>d</em> days is given by the function:

f(d)=5(1.02)^d

Part A)

We know that the radius of the algae was approximately 6.34 mm when the biologist concluded her study. To find the reasonable domain, we can substitute 6.34 for f(d) and solve for <em>d</em>. Therefore:

6.34=5(1.02)^d

Divide both sides by five:

(1.02)^d=1.268

Take the log of both sides with base 1.02:

\displaystyle d=\log_{1.02}1.268

Using the Change of Base Property, evaluate for <em>d: </em>

<em />\displaystyle d=\frac{\log 1.268}{\log 1.02}=11.9903...\approx 12<em />

So, the biologist concluded her study after 12 days.

Therefore, a reasonable domain to plot the growth function is:

0\leq d\leq 12

Part 2)

The <em>y-</em>intercept of the function is when <em>d</em> = 0. Find the <em>y-</em>intercept:

f(0)=5(1.02)^{(0)}=5(1)=5

Since <em>d</em> represent the amount of days after the study had begun, the <em>y-</em>intercept represents the radius of the algae on the initial day.

So, when the biologist started her study, the radius of the algae was five millimeters.

Part 3)

To find the average rate of change for a nonlinear function, we find the slope between the two endpoints on the interval.

We want to find the average rate of change of f(d) from <em>d</em> = 4 to <em>d</em> = 11.

Find the endpoints:

f(4)=5.4121...\text{ and } f(11)=6.2168...

And find the slope between them:

\displaystyle m=\frac{f(11)-f(4)}{11-4}=0.1149...\approx 0.11

Since f(d) measures millimeters and <em>d</em> measures days, this tells us that, on average, the radius of the algae grew by about 0.11 mm per day from the 4th day to the 11th day.

5 0
3 years ago
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