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Temka [501]
3 years ago
10

The distance d of a particle moving in a straight line is given by d(t) = 2t3 + 5t – 2, where t is given in seconds and d is mea

sured in meters. Find an expression for the instantaneous velocity v(t) of the particle at any given point in time.
Mathematics
1 answer:
Sedaia [141]3 years ago
8 0

Answer:

Step-by-step explanation:

hello,

v(t)=\dfrac{d(t)}{t}=2t^2+5-\dfrac{2}{t}

hope this helps

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Answer:

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I put a picture<br><br> —PLEASE HELP
Karo-lina-s [1.5K]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Base of a cube is a square, and in the given figure it's stated that the measure of each side is " x " ft

Therefore it's Area is equal to : -

  • side \times side

  • x \times x

  • {x}^{2}

Now, since it's Area is given as 1/4 ft², let's equate the Areas to find the measure of each side ~

that is ~

  • {x}^{2}  =  \dfrac{1}{4}

  • x =  \sqrt{ \dfrac{1}{2}  \times  \dfrac{1}{2} }

  • x =  \dfrac{1}{2}  \:  \: feet

It's time to find the volume of cube that is ~

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So, let's plug the value of side length (1/2 ft)

Volume is equal to ~

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I hope it helped ~

\mathrm{✌TeeNForeveR✌}

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