Answer: equation of the tangent plane is z = 1
Step-by-step explanation:
Given equation
z = e^(-x²-y²) at point (0,0,1)
now let z = f(x,y)
Δf(x,y) = [ fx, fy ]
= (-2xe^(-x²-y²)), (-2ye^(-x²-y²))
now
Δf (0,0) = [ 0, 0 ] = [ a, b ]
equation of the tangent plane therefore will be
z - z₀ = a(x-x₀) + b(y-y₀)
z - 1 = 0(x-0) + 0(y-0)
z - 1 = 0 + 0
z = 1
Therefore equation of the tangent plane is z = 1
Answer:
-11
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Step-by-step explanation:
<u>Step 1: Define</u>
x² + 9x + 3
x = -2
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em>: (-2)² + 9(-2) + 3
- Exponents: 4 + 9(-2) + 3
- Multiply: 4 - 18 + 3
- Subtract: -14 + 3
- Add: -11
Answer: this is the right answer Graph A represents j(x). The y-intercepts for f(x) and g(x) can be 1 and 3. And The rate of change of the sum of f(x) and g(x) is greater than that of either function. your welcome
Step-by-step explanation:
Part A.
In this part we have to find the increasing interval .
Increasing interval is that interval where graph goes up. And from the graph we can say that the graph goes up in the interval
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And that's the increasing interval .
Part B.
Correct option is B
x and y intercepts
x intercept is the point where graph touches the x axis. And the graph touches the x axis at x=-1 and 1 .
So the x intercepts are
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y intercepts are the point, where the graph touches or crosses the y axis.
Therefore the y intercept is (0,1)
So the correct option is D .