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3 years ago

What is the y-intercept of y=3-4xy=3−4xy, equals, 3, minus, 4, x?

Mathematics

1 answer:

balu736 [363]3 years ago

8 0

Answer:

y = 3 - 4x

To find the y intercept let x = 0

y = 3 - 4(0)

y = 3 or ( 0 ,3)

Hope this helps.

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Solve the word problem. Round your final result to the nearest hundredth.

fenix001 [56]

Answer:

1)Area of circle: 64 $\pi$

2)Area of semicircles: 128 $\pi$

3)Area of quarter-circles: 128 $\pi$

4)Total area of pattern: 320 $\pi$

Step-by-step explanation:

r = 8cm

Given: 1 circle, 4 semicircles, and 8 quarter-circles.

Area of a circle: $\pi r^{2}$

1) A = $\pi r^{2}$ where r = 8

A = 64 $\pi$

2) 4 semicircles = 2 circles

so the answer is 2*A = 128 $\pi$

3) 8 quarter-circles = 2 circles

Therefore, the answer here is the same as the answer for #2!

4)There are 5 circles total because:

1 circle = 1 circle

4 semicircles divided by 2 = 2 circles (because $\frac{1}{2}$ times 4)

8 quarter-circles divided by 4 (think about what "quarter" means) = 2 circles

So ... 1 + 2 + 2 = 5 circles

Now we need to find the area of 5 circles which is just 5*A

5*A = 320 $\pi$

4 0

2 years ago

Which angles are adjacent to eachother

JulsSmile [24]

Answer:

3 and 2 i'm pretty sure

Step-by-step explanation:

the ones they are next to

3 0

2 years ago

A regular pyramid has a square base with sides of length 1. The four triangular faces are isosceles triangles whose equal sides

lawyer [7]

Answer:

jiiiiiiiiiiiiiiiiiiiiiiiiiiiiii

Step-by-step explanation:

iiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii

5 0

3 years ago

What are the Ratio 4:5 and 8:10?

miv72 [106K]

Answer:

4/5 = 80% and 8/10 = 80%

Step-by-step explanation:

3 0

2 years ago

How many students must be randomly selected to estimate the mean weekly earnings of students at one college? We want 95% confide

kari74 [83]

Answer:

The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

Step-by-step explanation:

The (1 - α)% confidence interval for population mean (μ) is:

$CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}$

The margin of error of a (1 - α)% confidence interval for population mean (μ) is:

$MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}$

The information provided is:

σ = $60

MOE = $2

The critical value of z for 95% confidence level is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the sample size as follows:

$MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}$

$n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}$

$=[\frac{1.96\times 60}{2}]^{2}$

$=3457.44\\\approx 3458$

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

8 0

2 years ago