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8_murik_8 [283]
3 years ago
15

I need what is the slope of the line graphed

Mathematics
1 answer:
pentagon [3]3 years ago
3 0

Answer:

-3/5

Step-by-step explanation:

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Given the data set (18,14, 12, 14, 11, 11, 19, 20, 16, 11), which statements are correct?
Anuta_ua [19.1K]

The correct statement is that the <u>range of the data is 9</u>

<h3>Range of a data</h3>

The formula for calculating the range of data is expressed as:

Range = Highest value - Lowest value

From the given data

  • Highest value = 20
  • Lowest value = 11

Substituting into the formula

Range = 20 - 11

Range = 9

Hence the correct statement is that the <u>range of the data is 9</u>

Learn more on range here: brainly.com/question/2264373

6 0
2 years ago
A.2.00<br>b. 2.50<br>c 5.25<br>d 10.50 ​
klemol [59]

Answer:

the picture is blurry

Step-by-step explanation:

<h2>can. you give me another picture? plz</h2>
5 0
3 years ago
Write the equation of the line that passes through the points (3,-8) and (-8,1).
Gennadij [26K]

Answer:

-9/11

Step-by-step explanation:

-8-1/3-(-8)

-9/11

6 0
3 years ago
the half-life of a new experimental drug in your bloodstream is 15 hours how long will it take for the drug to Decay to 60% of t
Ierofanga [76]

4 hours? i may be wrong

i did - 60 * 15

seems about right, since 50% would be 7.5 hours?

7 0
3 years ago
Please anyone answer me
ollegr [7]

Let's divide the shaded region into two areas:

area 1: x = 0 ---> x = 2

ares 2: x = 2 ---> x = 4

In area 1, we need to find the area under g(x) = x and in area 2, we need to find the area between g(x) = x and f(x) = (x - 2)^2. Now let's set up the integrals needed to find the areas.

Area 1:

A\frac{}{1}  = ∫g(x)dx =  ∫xdx =  \frac{1}{2}  {x}^{2}  | \frac{2}{0}  = 2

Area 2:

A\frac{}{2}  = ∫(g(x) - f(x))dx

= ∫(x -  {(x - 2)}^{2} )dx

=  ∫( - {x}^{2}  + 5x - 4)dx

= ( - \frac{1}{3}{x}^{3} +   \frac{5}{2} {x}^{2}  - 4x)   | \frac{4}{2}

= 2.67 - ( - 0.67) = 3.34

Therefore, the area of the shaded portion of the graph is

A = A1 + A2 = 5.34

3 0
3 years ago
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