I need what is the slope of the line graphed

Which expression is equivalent to -9x^-1y^-9/-15x^5y^-3? Assume x is not equal to 0,y is not equal to 0

VladimirAG [237]

I am going to assume that "v" is meant to be a "y"
the answer is b. (3)/(5x^6 y^6)

7 0

2 years ago

janice wants to jog 3.25 miles on the treadmill she has jogged 1.63 miles how much farther does she have to jog to meet her goal

Mumz [18]

$3.25 - 1.63 = 1.62$
1.62 miles to go to reach her goal.

4 0

2 years ago

You saved $20,000.00 and want to diversify your monies. You invest 45% in a Treasury bond for 3 years at 4.35% APR compounded an

Maru [420]

Compound Interest

A total of $20,000 is invested in different assets.

45% is invested in a Treasury bond for 3 years at 4.35 APR compounded annually.

For this investment, the principal is P = 0.45*$20,000 = $9,000.

The compounding period is yearly, thus the interest rate is:

i = 4.35 / 100 = 0.0435

The duration (in periods) is n = 3

Calculate the final value with the formula:

$M=P_{}(1+i)^n$

Substituting:

$\begin{gathered} M=\$9,000_{}(1+0.0435)^3 \\ M=\$9,000\cdot1.136259062875 \\ M=\$10,226.33 \end{gathered}$

The second investment is a CD at 3.75% APR for 3 years compounded annually. The parameters for the calculations are as follows:

P = 15% of $20,000 = $3,000

i = 3.75 / 100 = 0.0375

n = 3

Calculating:

$\begin{gathered} M=\$3,000_{}(1+0.0375)^3 \\ M=\$3,000\cdot1.116771484375 \\ M=\$3,350.31 \end{gathered}$

The third investment is in a stock plan. The initial value of the investment is

P = 20% of $20,000 = $4,000

By the end of the first year, the stock plan increased by 8%, thus its value is:

M1 = $4000 * 1.2 = $4,800

By the end of the second year, the stock plan decreased by 4$, thus the value is:

M2 = $4,800 * 0.96 = $4,608

Finally, the stock plan increases by 6%, resulting in a final balance of:

M3 = $4,608 * 1.06 = $4,884.48

Finally, the last investment is in a savings account at 2.90% APR compounded annually for 3 years (not mentioned, but assumed).

P = $20,000 - $9,000- $3,000 - $4,000 = $4,000

i = 2.90 / 100 = 0.029

n = 3

Calculating:

$\begin{gathered} M=\$4,000_{}(1+0.029)^3 \\ M=\$4,000\cdot1.089547389 \\ M=\$4,358.19 \end{gathered}$

To summarize, the final balances for each type of investment at the end of the third year are:

Investment 1; $10,226.33

Investment 2: $3,350.31

Investment 3: $4,884.48

Investment 4: $4,358.19

Total balance: $22,819.32

3 0

1 year ago

write balanced chemical equation for the process of photosynthesis giving the physical state of all the substances involved in t

RideAnS [48]

Answer:

The process of photosynthesis is commonly written as: 6CO2 + 6H2O → C6H12O6 + 6O2.

Step-by-step explanation:

3 0

2 years ago

at 1:30 in the afternoon an old freight train and a new dart express train pull out of the new garland station going in opposite

nydimaria [60]

Solution: The speed of old freight train is 0.5 miles per minute and the speed of new dart express train is 1.5 miles per minute.

Explanation:

Let the speed of old freight train is x miles per minute and the speed of new dart express train is y miles per minute.

It is given that the speed of the dart express train is three times faster than the freight train. So, it can be written as,

$3x=y$ ....(1)

The trains are moving towards the opposite directions, therefore the distance between them is increased at the speed of $(x+y)$ miles per minute.

$Distance=Speed\times Time$

The distance between both train in 15 minutes is represented by $15(x+y)$ .

According to the given information the distance between trains is 30 miles in 15 minutes.

$15(x+y)=30$

$x+y=2$

Use equation (1) and put $y=3x$

$x+3x=2$

$4x=2$

$x=0.5$

Put this value in equation (1), to find the value of y.

$y=3(0.5)$

$y=1.5$

Therefore, the The speed of old freight train is 0.5 miles per minute and the speed of new dart express train is 1.5 miles per minute.

4 0

3 years ago