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Vesna [10]
3 years ago
9

How to graph Y greater than or equal to 2

Mathematics
1 answer:
zubka84 [21]3 years ago
5 0

Answer:

<h2>Check the image as well as the explanation.</h2>

Step-by-step explanation:

In order to graph y\geq 2, we first need to graph y = 2.

y = 2 is a straight line which will be parallel to the x-axis.

We need to graph y \geq 2.

3, 4, 5......> 2. That is, all these values satisfies y \geq 2.

Hence, the will be the area towards the points y = 3 / 4 / 5 / ......

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Answer:

The second option though i can not really see it.

3 0
3 years ago
In na hour , a jogger burns about 4 calories pero pound of body weight. How Manu calories will a jogger who weighs 151 pounds in
Alex777 [14]

This is a rate*unit problem.


So, 4 calories per pound x 151 pounds

4\times151=604

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6 0
3 years ago
If you use the addition property of equality , what number would you add to both sides of the equal sign to isolate the variable
kkurt [141]

Answer:

The answer is "\frac{26}{7}"

Step-by-step explanation:

The whole question can be found in the file attached.

\to x + \frac{5}{7} = \frac{31}{7}\\\\

Subtracting the \frac{5}{7} from both sides of the equations:

\to x +\frac{5}{7}  - \frac{5}{7}  = \frac{31}{7}  - \frac{5}{7} \\\\

                    = \frac{31-5}{7} \\\\= \frac{26}{7} \\\\

5 0
3 years ago
Rico paid $180 sales tax on his new $2,400 motorcycle. What was the sales tax percentage rate where he bought his motorcycle?
liraira [26]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
the length of a rectangle is 2 in more than it's w i d t h the area of a rectangle is equal to 1 inch less than three times a pe
Marizza181 [45]
If we let x and y represent length and width, respectively, then we can write equations according to the problem statement.
.. x = y +2
.. xy = 3(2(x +y)) -1

This can be solved a variety of ways. I find a graphing calculator provides an easy solution: (x, y) = (13, 11).

The length of the rectangle is 13 inches.
The width of the rectangle is 11 inches.

______
Just so you're aware, the problem statement is nonsensical. You cannot compare perimeter (inches) to area (square inches). You can compare their numerical values, but the units are different, so there is no direct comparison.

6 0
3 years ago
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