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Vesna [10]
4 years ago
9

How to graph Y greater than or equal to 2

Mathematics
1 answer:
zubka84 [21]4 years ago
5 0

Answer:

<h2>Check the image as well as the explanation.</h2>

Step-by-step explanation:

In order to graph y\geq 2, we first need to graph y = 2.

y = 2 is a straight line which will be parallel to the x-axis.

We need to graph y \geq 2.

3, 4, 5......> 2. That is, all these values satisfies y \geq 2.

Hence, the will be the area towards the points y = 3 / 4 / 5 / ......

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2. Suppose that P(A) = 0.32, P(B) = 0.46, P(C) = 0.23, P(A ∪ B) = 0.57, P(A ∪ C) = 0.55, P(B ∪ C) = 0.49. a. Compute P(B ′ ). b.
Liula [17]

Answer:

Step-by-step explanation:

From the given information:

a.

Compute P(B'):

P(B') = 1 - P(B) \\ \\P(B') = 1 - 0.46 \\ \\ P(B') = \mathbf{0.54}

b.

Compute P(A ∩ B)

P(A ∩ B) =  P(A) +P(B) - P(A∪B)

P(A ∩ B) =  0.32 + 0.46 - 0.57

P(A ∩ B) =  0.21

Thus, since P(A ∩ B) ≠ 0, we can say that they are not mutually exclusive.

c.

P(A ∩ C) = P(A) +P(C) - P(A∪C)

P(A ∩ C) = 0.32 + 0.23 -0.55

P(A ∩ C) =  0

Thus, since P(A ∩ C) = 0, we can say that they are both mutually exclusive.

d. To determine  P[(A ∪ B ∪ C)′]

i.e. none of the events occurring

Then :

P(B ∩ C) = 0.46 +0.23 -0.49

P(B ∩ C) = 0.20

Therefore:

P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A ∩ B ) - P(A  ∩ C) - P(B ∩ C)  + P(A ∩ B ∩ C)

P(A ∪ B ∪ C) = 0.32 + 0.46 + 0.23 - 0.21 - 0 - 0.20 + 0

P(A ∪ B ∪ C) = 0.60

3 0
3 years ago
34= -62 +3x mixed equation
Rama09 [41]

Answer:

32

Step-by-step explanation:

34 = -62 + 3x

34+62 = 3x

96 = 3x

x = 32

5 0
4 years ago
Read 2 more answers
Please answer with explanation
NARA [144]

Answer:

2000 feet.

Step-by-step explanation:

Let the length of fence need be x feet.

Then we have the equation:

2lx = 19x + 4000

21x - 19x = 4000

2x = 4000

x = 2000.

4 0
3 years ago
Which descriptions from the list below accurately describe the relationship
Sphinxa [80]

Answer:

A) Same shape

C) Similar

Step-by-step explanation:

The figure is missing: find it in attachment.

Here we want to compare the two triangles: Let's analyze each statement.

A) Same shape --> TRUE

In fact, we see that the 3 angles of the two triangles are the same: therefore, the two triangles have same shape.

B) Congruent --> FALSE

Two triangles are said to be congruent if they have same sizes and same angles: here we see that they do not have the same sizes, so they are not congruent.

C) Similar --> TRUE

Two triangles are said to be similar if the proportions between their sides are the same.

For the triangles in the figure, we see that this is valid. In fact, the ratio of the 3 sides for the triangle on the left is 10:8:6, while the ratio for the triangle on the right is 20:16:12, which can be reduced to 10:8:6: therefore, the same ratio.

D) Same size --> FALSE

As we see, the two triangles do not have the same size.

7 0
4 years ago
A box of shapes contains 3 rectangles, 5 triangles, and 7 hexagons. What is the probability of drawing a triangle or a hexagon?
Kipish [7]
There are 5 + 7 = 12 triangles or hexagons. So the probability is 12/15 = 4/5. As a percent, it would be 80%.
---
Hope this helps!
==jding713==
7 0
4 years ago
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