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3 years ago

What's the answer to this math question

Mathematics

1 answer:

fenix001 [56]3 years ago

7 0

Im not exactly sure but i think:

r^2+6r+2
________
5r^2-5r-25

remember IM NOT SO SURE

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The median is 44 (the center line)

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3 years ago

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In a grocery store there are three choices of size for your favorite laundry detergent. 1) A 24 ounce bottle for $4.99 2) A 48 o

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3 years ago

Express 510 & 3/10 % as a decimal fraction.

Naddika [18.5K]

Answer:

5.10 and 0.3

Step-by-step explanation:

510% in decimal form is 5.10 if u move the decimal to the left twice

3/10% is 30% which in decimal from is .3 if u move the decimal over to the left twice

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3 years ago

Add and simplify 7/8+ 1/6

Svet_ta [14]

Answer:

17/24

Step-by-step explanation:

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3 years ago

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A population of values has a normal distribution with μ=204.9μ=204.9 and σ=81.9σ=81.9. You intend to draw a random sample of siz

marin [14]

Answer:

7. μ=204.9 and σ=5.4968

8. μ=75.9 and σ=0.7136

9. p=0.9452

Step-by-step explanation:

7. - Given that the population mean =204.9 and the standard deviation is 81.90 and the sample size n=222.

-The sample mean, $\mu_x$ is calculated as:

$\mu_x=\mu=204.9, \mu_x=sample \ mean$

-The standard deviation, $\sigma_x$ is calculated as:

$\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{81.9}{\sqrt{222}}\\\\=5.4968$

8. For a random variable X.

-Given a X's population mean is 75.9, standard deviation is 9.6 and a sample size of 181

-#The sample mean, $\mu_x$ is calculated as:

$\mu_x=\mu\\\\=75.9$

#The sample standard deviation is calculated as follows:

$\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{9.6}{\sqrt{181}}\\\\=0.7136$

9. Given the population mean, μ=135.7 and σ=88 and n=59

#We calculate the sample mean;

$\mu_x=\mu=135.7$

#Sample standard deviation:

$\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{88}{\sqrt{59}}\\\\=11.4566$

#The sample size, n=59 is at least 30, so we apply Central Limit Theorem:

$P(\bar X>117.4)=P(Z>\frac{117.4-\mu_{\bar x}}{\sigma_x})\\\\=P(Z>\frac{117.4-135.7}{11.4566})\\\\=P(Z>-1.5973)\\\\=1-0.05480 \\\\=0.9452$

Hence, the probability of a random sample's mean being greater than 117.4 is 0.9452

7 0

3 years ago